To answer this question, you need to know that a quarter is worth $0.25 and dimes worth $0.10. In this case, the total number of money that made from quarters and dimes is $2.80
With Q=quarter and D=dime, then the equation should be:
2.80= 0.25 Q + 0.10 D
The condition that needs to be fulfilled in this case is that the quarter should be 8 more than dimes. Then you need to find out the highest possible number of the quarter and lowest possible number of the dimes.
If you divide 2.8 with 0.25 you will found it will be 11.2 but 11 quarter will result with 0.05 value which you cannot remove, so the highest possible of the quarter should be 10.
If the highest possible of the quarter is 10, then the lowest possible of dimes should be:
2.8= 0.25(10) + 0.10D
0.10D= 0.3
D=3
Since 10-3 is 7, then it is not possible for the quarter to be 8 more than the dimes.
Answer: a 20% chance
Step-by-step explanation:
All you need to do is 2/10 = .2 = 20%
We do this because if 2 chose to read and there are 10 kids.
Hey there Mejia021274,
1) Independent systems have exactly one solution:
x + y = 1
x - y = 3
x = 2, y = -1
2) Inconsistent systems have no solutions :
5x + y = 6
5x + y = 10
There is no solution as 5x + y cannot be equal to 6 and 10
3) Consistent systems have a lot of solutions:
x+y = 5
<span>2x+2y = 10 </span>
<span>A few solutions to this system are (1,4), (2,3), (3,2), (4,1), (5,0), and so on.
</span>
Hope this helps :))
~Top
Hey there! I'm happy to help!
First, let's find the area of the top of the bar.
30×70=2100
This is the same as the bottom of the bar, so we have another 2100 mm, giving us 4200 in total.
Now we want to find the two long sides. This is 70×4.5, which is 315. Since there are two of these sides, we have another 315, giving us 630 in total there.
Now we have the short sides.
30×4.5=135
135×2=270
Now, we add up all of these measurements.
4200+630+270=5100
Therefore, Will's Wrapping Company will need 5100 mm² of paper to make their wrapper.
Have a wonderful day! :D
You just have to add the numbers up.
So the perimeter is 47 ft.
