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3 years ago

Find the sum of 16y² and -5y²

Mathematics

1 answer:

nalin [4]3 years ago

4 0

Answer:

11y²

Step-by-step explanation:

16y² + -5y²

So in this expression ignore y² and solve 16 + -5

Since both terms are like terms you can add

16 + -5

= 11

____________________________________________________________

Now add y² to your answer

= 11y²

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The mean lifetime of a certain tire is 30,000 miles and the standard deviation is 2500 miles. If we assume nothing about the sha

kati45 [8]

A standard deviation is 2500 miles, so the range of 25,000 to 37,500 is 2 standard deviations below, and 3 standard deviation above the mean of 30,000.
We aren't assuming anything about the distribution, but we sort of have to assume a normal distribution in order to answer. When you don't know anything about a distribution, this is generally what you do.
The general rule for standard deviations is:
+/- 1 SD: +/- 34% of population, for a total of 68%
+/- 2 SD: Another 14% in either direction, for a total of 96% of population.
+/- 3 SD, Another 2% in either direction, which pretty much captures the entire distribution (4 standard deviations from the mean is incredibly rare/unlikely)
We have a range of +/- 1 SD, so we know that 68% percent o the tire 'population' is captured in the range. We also have one more standard deviation in both directions, so we add 28% to this number to get 96% of the population. We have a third standard deviation above the mean, so we add another 2% to arrive at 98% of the population.

Answer is 98% of all such tires.

5 0

3 years ago

What's 2.5 divided by 5

USPshnik [31]

Your answer would be 0.5 ;) Hope this helps

3 0

3 years ago

You toss a fair number cube with 1 to 6 and flip a coin.

ludmilkaskok [199]

Answer:

1/6

Step-by-step explanation:

its unlikley because 1 out of 6 chances that youll land on a six or something and a 50 50 chance that you'll land on heads or tails. Unlikcry for te dice rills and likekly for the coins toss

8 0

3 years ago

Which could be the entire interval over which the function f(x) is positive

aalyn [17]

$(-\infty,-2) \cup(2,\infty)$

<h2>Explanation:</h2>

Remember you need to write complete questions in order to find exact answers. In this way you haven't provided any function, so I'll choose a quadratic function given by:

$f(x)=x^2-4x$

So we need to find the entire interval at which this function positive. Put another way:

$f(x)>0$

By using graphing tool, we get the graph shown below. As you can see:

The function decreases from $x=-\infty \ to \ x=0$

The function increases from $x=0 \ to \ x=\infty$
The graph of the function is a parabola that opens up.

But what is really importan in this problem is that:

The function is positive over the interval $(-\infty,-2) \cup(2,\infty)$

At this interval the function is positive, that is, $f(x)>0$

<h2>Learn more:</h2>

Standard equation of the graph of a parabola:

brainly.com/question/12896871

#LearnWithBrainly

7 0

3 years ago

An engineer is comparing voltages for two types of batteries (K and Q) using a sample of 37 type K batteries and a sample of 58

Olegator [25]

Answer:

Hypothesis Test states that we will accept null hypothesis.

Step-by-step explanation:

We are given that an engineer is comparing voltages for two types of batteries (K and Q).

where, $\mu_1$ = true mean voltage for type K batteries.

$\mu_2$ = true mean voltage for type Q batteries.

So, Null Hypothesis, $H_0$ : $\mu_1 = \mu_2$ {mean voltage for these two types of

batteries is same}

Alternate Hypothesis, $H_1$ : $\mu_1 \neq \mu_2$ {mean voltage for these two types of

batteries is different]

<em>The test statistics we use here will be :</em>

$\frac{(X_1bar-X_2bar) - (\mu_1 - \mu_2) }{s_p\sqrt{\frac{1}{n_1}+\frac{1}{n_2} } }$ follows $t_n__1 + n_2 -2$

where, $X_1bar$ = 8.54 and $X_2bar$ = 8.69

$s_1$ = 0.225 and $s_2$ = 0.725

$n_1$ = 37 and $n_2$ = 58

$s_p = \sqrt{\frac{(n_1-1)s_1^{2}+(n_2-1)s_2^{2} }{n_1+n_2-2} } = \sqrt{\frac{(37-1)0.225^{2}+(58-1)0.725^{2} }{37+58-2} }$ = 0.585 Here, we use t test statistics because we know nothing about population standard deviations.

Test statistics = $\frac{(8.54-8.69) - 0 }{0.585\sqrt{\frac{1}{37}+\frac{1}{58} } }$ follows $t_9_3$

= -1.219

<em>At 0.1 or 10% level of significance t table gives a critical value between (-1.671,-1.658) to (1.671,1.658) at 93 degree of freedom. Since our test statistics is more than the critical table value of t as -1.219 > (-1.671,-1.658) so we have insufficient evidence to reject null hypothesis.</em>

Therefore, we conclude that mean voltage for these two types of batteries is same.

6 0

3 years ago