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2 years ago

(7,-5) and (6,r) m=0

Mathematics

1 answer:

valina [46]2 years ago

3 0

Answer:

is right answer = 2 is a correct answer

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Find x. Round your answer to the nearest tenth of a degree . Please help I will mark brainliest

Oksana_A [137]

Using trigonometric ratio, the value of x is 63.6°

<h3>Trigonometric Ratio</h3>

This is the ratios of sides of a right-angled triangle with respect to any of its acute angles are known as the trigonometric ratios of that particular angle.

Trigonometric ratio are often coined as SOHCAHTOA

In the given triangle, we need to find the value of x using trigonomtric ratio.

Since we have the value of adjacent and hypothenuse, we definitely need to use cosine

cosθ = adjacent / hypothenuse

adjacent = 4

hypothenuse = 9

Substituting the values into the equation;

cos θ = 4 / 9

cos θ = 0.444

θ = cos⁻¹ 0.4444

θ = 63.6°

Learn more on trigonometric ratio here;

brainly.com/question/24349828

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7 0

1 year ago

Answer and explain it please

satela [25.4K]

Answer:

363 inches squared

Step-by-step explanation:

Area = $\pi*11^2$ . $\pi$ is 3 so it's just 11 squared times 3. Which is 121 times 3. That equals 363.

4 0

2 years ago

Find the roots of:

Elena-2011 [213]

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

| 2 -7 8 -3

| 2 -5 3 0

2 -3 0

So the factorization is (x-1)² (2x-3)=0. So:

$\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

| 1 -1 0 -4

1 2 2 0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

$\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

| 6 7 9 2

6 -5 1 0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

$\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}$

$\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}$