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3 years ago

1/6 + -2/3 = ? I’ll give best review

Mathematics

1 answer:

Mice21 [21]3 years ago

3 0

1/6 + -2/3=
1/6- 2/3 | get 2/3 to be over 6 (3 goes into 6 twice so we multiply 2 by 2)
1/6- 4/6
=-3/6
=-1/2

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GIVEN BRAINLIEST, 5 STARS, + THANKS

Ede4ka [16]

Answer:

<u>Option B. Side YZ is the same length as side Y'X'.</u>

Step-by-step explanation:

XYZ is reflected across the y-axis and then translated down 6 units to form X'Y'Z'.

So, X' is the image of point X

Y' is the image of point Y

Z' is the image of point Z

And ΔXYZ ≅ ΔX'YΔ'Z'

And the corresponding length are congruent

We will check the options:

A. X has the same measure as X'. ⇒ True

B. Side YZ is the same length as side Y'X'. ⇒ Wrong

Because YZ will be translated to Y'Z'

C. Z has the same measure as Z'. ⇒ True

D. Side XZ is the same length as side X'Z'. ⇒ True

<u>So, The answer is option B. Side YZ is the same length as side Y'X'.</u>

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3 years ago

Mike drove 475 miles on tuesday.on wednesday he drove 498 mikes.how many miles did he drive

Bumek [7]

I believe it is 973 miles if you just add the amount on Tuesday + the amount on Wednesday so....
475+498=973

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3 years ago

Read 2 more answers

If the endpoints of the diameter of a circle are (−8, −6) and (−4, −14), what is the standard form equation of the circle?

kondaur [170]

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

Solution:

The endpoints of the diameter of a circle are (–8, –6) and (–4, –14).

Center of the circle = Mid point of the diameter

Mid point formula:

$$P(x, y)=\left(\frac{x_{1}+x_{2}}{2}, \frac{y_{1}+y_{2}}{2}\right)$

Here, $x_1=-8, y_1=-6, x_2=-4, y_2=-14$

$$P(x, y) =\left(\frac{-8-4}{2}, \frac{-6-14}{2}\right)$

$$P(x, y) =\left(\frac{-12}{2}, \frac{-20}{2}\right)$

$$P(x, y) =(-6, -10)$

Center of the circle = (–6, –10)

Radius is the distance between center and any endpoint of the diameter.

To calculate the radius using distance formula.

$r=\sqrt{\left(x_{2}-x_{1}\right)^{2}+\left(y_{2}-y_{1}\right)^{2}}$

Here, $x_1=-6, y_1=-10, x_2=-8, y_2=-6$

$r=\sqrt{\left(-8-(-6)\right)^{2}+\left(-6-(-10)}\right)^{2}}$

$r=\sqrt{(-8+6)^{2}+(-6+10)^{2}}$

$r=\sqrt{(-2)^{2}+(4)^{2}}$

$r=\sqrt{20}$ units

The standard form of the equation of a circle is

$(x-a)^{2}+(y-b)^{2}=r^{2}$ , where (a, b) are center and r is the radius.

Here, center = (–6, –10) and $r=\sqrt{20}$

$(x-(-6))^{2}+(y-(-10))^{2}={(\sqrt{20})} ^{2}$

$(x+6)^{2}+(y+10)^{2}=20$

Equation of the circle is $(x+6)^{2}+(y+10)^{2}=20$ .

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vivado [14]

Step-by-step explanation:

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VikaD [51]

Answer:

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Step-by-step explanation:

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2 years ago