Answer:
a1 = 39, a2 = 41, a3 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Step-by-step explanation:
Let the first integer be a1 = a.
Let the second odd integer be a2 = a + 2
Let the third odd integer be a3 = (a + 2) + 2 = a + 4
The sum of three consecutive odd integers is 123.
123 = a1 + a2 + a3
123 = a + (a + 2) + (a + 4)
123 = 3a + 6
117 = 3a
a = 39
a1 = a = 39
a2 = a + 2 = 39 + 2 = 41
a3 = a + 4 = 39 + 4 = 43
The pair with the greatest sum is a2 + a3 = 41 + 43 = 84
Answer:
20
Step-by-step explanation:
If they were whole itd be ten but there halves so 20
She made 15 cookies
<em><u>Solution:</u></em>
Let "x" be the number of cookies she made
She gave 1/3 of cookies for her husband
Therefore,

Find the remaining

1/4 of the cookies to her son
Therefore,

Now again find the remaining

1/6 of a cookies to her neighbor

Now again find the remaining

She ate the remaining six cookies
Therefore,

Thus she made approximately 15 cookies
(-2)^4=16
(-2)^-1=-1/2
-1/2x16=-8
Answer: -8
The answer is 8 3/4,hope Ive helped xx