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Jet001 [13]
3 years ago
14

Enter the number using calculator notation. 8.5x 103 The number in calculator notation is

Mathematics
1 answer:
BabaBlast [244]3 years ago
4 0

Answer: 875.5x

Step-by-step explanation:

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Where v is the final velocity (in m/s), u is the initial velocity (in m/s), a is the acceleration (in m/s²) and s is the distanc
drek231 [11]

Answer:

C. 178−−−√ m

Step-by-step explanation:

Given the following :

v = final velocity (in m/s)

u = initial velocity (in m/s)

a = acceleration (in m/s²)

s = distance (in meters).

Find v when u is 8 m/s, a is 3 m/s², and s is 19 meters

Using the 3rd equation of motion :

v^2 = u^2 + 2as

v^2 = 8^2 + 2(3)(19)

v^2 = 64 + 114

v^2 = 178

Take the square root of both sides :

√v^2 = √178

v = √178

6 0
3 years ago
Use lagrange multipliers to find the shortest distance, d, from the point (4, 0, −5 to the plane x y z = 1
Varvara68 [4.7K]
I assume there are some plus signs that aren't rendering for some reason, so that the plane should be x+y+z=1.

You're minimizing d(x,y,z)=\sqrt{(x-4)^2+y^2+(z+5)^2} subject to the constraint f(x,y,z)=x+y+z=1. Note that d(x,y,z) and d(x,y,z)^2 attain their extrema at the same values of x,y,z, so we'll be working with the squared distance to avoid working out some slightly more complicated partial derivatives later.

The Lagrangian is

L(x,y,z,\lambda)=(x-4)^2+y^2+(z+5)^2+\lambda(x+y+z-1)

Take your partial derivatives and set them equal to 0:

\begin{cases}\dfrac{\partial L}{\partial x}=2(x-4)+\lambda=0\\\\\dfrac{\partial L}{\partial y}=2y+\lambda=0\\\\\dfrac{\partial L}{\partial z}=2(z+5)+\lambda=0\\\\\dfrac{\partial L}{\partial\lambda}=x+y+z-1=0\end{cases}\implies\begin{cases}2x+\lambda=8\\2y+\lambda=0\\2z+\lambda=-10\\x+y+z=1\end{cases}

Adding the first three equations together yields

2x+2y+2z+3\lambda=2(x+y+z)+3\lambda=2+3\lambda=-2\implies \lambda=-\dfrac43

and plugging this into the first three equations, you find a critical point at (x,y,z)=\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right).

The squared distance is then d\left(\dfrac{14}3,\dfrac23,-\dfrac{13}3\right)^2=\dfrac43, which means the shortest distance must be \sqrt{\dfrac43}=\dfrac2{\sqrt3}.
7 0
3 years ago
NEED HELP ASAP What is true about the points on the graph of Y=3^x?
galben [10]

Answer:

d

Step-by-step explanation:

The answe of this question is d

3 0
3 years ago
What is 4231 divided by 13 ? Please simplify and show the original answer without simplifying .
Vinvika [58]
Simplified is 325 and not simplified is 325.561
4 0
3 years ago
How do u do (number 30)... please list step by step... <br><br>​
andrezito [222]

Answer:

the screen is really blurry sorry bout that

Step-by-step explanation:

3 0
3 years ago
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