A=600⋅(1.0001)^365t
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1: y=8, (-2,8)
2: y=6, (-1,6)
3: y=0, (2,0)
Step-by-step explanation:
Insert the x value into each equation then see what value of y that you need to get 4 on the right hand side of the equation.
Start by decomposing the number inside the root into primes
Then group the terms into cubes if possible

rewrite the root
![\sqrt[3]{80}=\sqrt[3]{10\cdot2^3}](https://tex.z-dn.net/?f=%5Csqrt%5B3%5D%7B80%7D%3D%5Csqrt%5B3%5D%7B10%5Ccdot2%5E3%7D)
then cancel the terms that are cubes and bring them out of the root
No they are not equivalent and if you are trying to get a mixed number try dividing
Answer:
the directrix and focus the axis of symmetry (goes through the focus, at right angles to the directrix) the vertex (where the parabola makes its sharpest turn) is halfway between the focus and directrix.
Step-by-step explanation: