Answer:
Diameter = 9
Step-by-step explanation:
Let the diameter be represented as x.
Based on the secant-tangent theorem, the following equation representing the relationship between the segments would be:
(16 + x)(16) = 20²
256 + 16x = 400
Subtract 256 from each side
16x = 400 - 256
16x = 144
Divide both sides by 16
x = 144/16
x = 9
Diameter = 9
Answer:
The left side 45.041¯645.0416‾ is not less than the right side 42 which means that the given statement is false.
10/8 in simplest form:
First, we can start off by finding the GCF of the denominator and the numerator. To do so, we need to list the factors of each of them and find the common ones.
Factors of 10: 1, 2, 5, 10
Factors of 8: 1, 2, 4, 8
We can see that our common factors are 1 and 2, considering that both the numerator and denominator has the same factors (1 and 2). Since we have our common factors, we need to find the greatest. Which is the greatest out of 1 and 2? The GCF is 2 because it is bigger than 1.
Second, divide the numerator and the denominator by the GCF (2).

Third, now we can revise our fraction and turn it into the simplest form. Take the two numbers you just got above us and put them in their numerator and denominator spot. You should get:

Answer in fraction form:

Answer in decimal form:

Answer in mixed number form:
Answer/Step-by-step explanation:
✔️The rate of change can be calculated using the coordinates of any two points on the graph. Let's use (2, 60) and (3, 75):

Rate of change (m) = 15
✅In the context of this situation, the rate of change can be interpreted to be the additional fee per class. Thus, an additional fee per class cost $15.
✔️Initial value is the same as the y-intercept.
To find the y-intercept (b), substitute m = 15, x = 2, and y = 60 into y = mx + b.
Thus:
60 = 15(2) + b
60 = 30 + b
60 - 30 = b
30 = b
b = 30
The initial value/y-intercept = $30
✅In this context, $30 is the start-up fee to cover art supplies.
Answer:
15th term =29/3
16th term = 31/3
Step-by-step explanation:
Given an arithmetic sequence with the first term a1 and the common difference d , the nth (or general) term is given by an=a1+(n−1)d .
First we find the 15th term
n=15
a1=1/3
d=1 - 1/3 = 2/3
Solution
1/3+(15-1)2/3
1/3+28/3
(1+28)/3
29/3
Lets find the 16th term
1/3+(16-1)2/3
1/3+30/3
(1+30)/3
31/3