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Rom4ik [11]
3 years ago
5

Decide what values of the variable cannot be solutions for each equation.

Mathematics
2 answers:
liraira [26]3 years ago
7 0

Step-by-step explanation:

\frac{1}{4x}  -  \frac{2}{x}  = 3 \\  \frac{1}{4x}  -  \frac{2}{x}  \times  \frac{4}{4}  = 3 \\  \frac{1}{4x}  -  \frac{8}{4x}  = 3 \\  \frac{1 - 8}{4x}  = 3 \\  \frac{ - 7}{4x}  = 3 \\ 4x =  \frac{ - 7}{3}  \\ x =  \frac{ - 7}{12}  \\ thank \: you

melomori [17]3 years ago
3 0

Answer:

→ \frac{1}{4x} -  \frac{2}{x}   = 3 \\ \frac{1}{4x} -  \frac{(2 \times 4)}{(x \times 4)}   = 3 \\ \frac{1}{4x}  -  \frac{8}{4x}  = 3 \\  \frac{(1 - 8)}{4x}  = 3 \\  \frac{( - 7)}{4x}  = 3 \\ \frac{1}{x}=  \frac{(3 \times 4)}{( - 7)}  \\ \frac{1}{x}=  \frac{12}{( - 7)} \\ \boxed{x =  \frac{( - 7)}{12} }

  • <u>x = -7/12</u> is the right answer.
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