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NNADVOKAT [17]
3 years ago
11

PLEASE HELP will give 99 points.

Mathematics
2 answers:
Yuri [45]3 years ago
8 0
The answer is 90 + 45 because BOC is a right angled triangle where angle BOC is 90 and angle BOK is 45 because 90 ÷2. A OK Is a right angled triangle so angle AOB is 90 as well so to find angle AOK we plus 90 and 45 which is 135 degrees.
liberstina [14]3 years ago
7 0

Answer:

135°

Step-by-step explanation:

I made a whole PNG to attach with the work on it but it wouldn't load to attach and I'm not about to type it all out xD

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X^2 + 2x + 5 find the zeros
Dvinal [7]

Answer:

Step-by-step explanation:

This is what I got

8 0
3 years ago
A coin is flipped four times, and the result is recorded for each flip. How many possible outcomes are there for the experiment?
stira [4]
To find this out multiply 2 * 2 * 2 * 2 to get 16 possible combinations
7 0
3 years ago
Sid and Libby are planning to sell pies at a local fair. They spend $200 to rent a table at the fair. Their costs for ingredient
pychu [463]
Sid and Libby are planning to sell pies at a local fair.
=> $200 to rent a table at the fair.<span>
=>  $3.00 per pie </span>costs for ingredients, other supplies, baking, and packaging<span>
They plan to sell the pies for $8 each. 
Let's find out how many pies will they be selling inorder to gain profit
=> 200 + 3.00(n) = 8(n), where n is the number of pie.
Let's try 40
=> 200 + 3(40) = 8 (40)
=> 320 = 320 
</span>=> 200 + 3(41) = 8 (41)
=> 323 = 328
<span>Thus, in their 41st pie, they will get a profit

</span>
4 0
3 years ago
Find the term indecent of x in the expansion of (x^2-1/x)^6
Mars2501 [29]

By the binomial theorem,

\displaystyle \left(x^2-\frac1x\right)^6 = \sum_{k=0}^6 \binom 6k (x^2)^{6-k} \left(-\frac1x\right)^k = \sum_{k=0}^6 \binom 6k (-1)^k x^{12-3k}

I assume you meant to say "independent", not "indecent", meaning we're looking for the constant term in the expansion. This happens for k such that

12 - 3k = 0   ===>   3k = 12   ===>   k = 4

which corresponds to the constant coefficient

\dbinom 64 (-1)^4 = \dfrac{6!}{4!(6-4)!} = \boxed{15}

3 0
3 years ago
I need help on the second one
dlinn [17]
It would be reproduction
3 0
3 years ago
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