All categories

4 years ago

PLEASE HELP will give 99 points.

Mathematics

2 answers:

Yuri [45]4 years ago

8 0

The answer is 90 + 45 because BOC is a right angled triangle where angle BOC is 90 and angle BOK is 45 because 90 ÷2. A OK Is a right angled triangle so angle AOB is 90 as well so to find angle AOK we plus 90 and 45 which is 135 degrees.

liberstina [14]4 years ago

7 0

Answer:

135°

Step-by-step explanation:

I made a whole PNG to attach with the work on it but it wouldn't load to attach and I'm not about to type it all out xD

You might be interested in

Convert 2.251 and 2.295 to meters. Write an equation<br><br>Thank You so very much if you help.

Anon25 [30]

2.251 cm
2.295 cm
2.3 cm

1 Metre is equal to 100 Centimetres

so To get from Cm to M we have to divide by 100

2.251 / 100 = 0.02251 m
2.295 / 100 = 0.02295 m
2.3 / 100 = 0.023 m

5 0

3 years ago

Hi, can you please help?

AnnyKZ [126]

Answer:

Step-by-step explanation:

your photo is blurry but I made most of it out and believe that the answer is A. 16

4 0

4 years ago

Consider the matrix A. A = 1 0 1 1 0 0 0 0 0 Find the characteristic polynomial for the matrix A. (Write your answer in terms of

dusya [7]

Answer with Step-by-step explanation:

We are given that a matrix

$A=\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]$

a.We have to find characteristic polynomial in terms of A

We know that characteristic equation of given matrix $\mid{A-\lambda I}\mid=0$

Where I is identity matrix of the order of given matrix

I= $\left[\begin{array}{ccc}1&0&0\\0&1&0\\0&0&1\end{array}\right]$

Substitute the values then, we get

$\begin{vmatrix}1-\lambda&0&1\\1&-\lambda&0\\0&0&-\lambda\end{vmatrix}=0$

$(1-\lambda)(\lamda^2)-0+0=0$

$\lambda^2-\lambda^3=0$

$\lambda^3-\lambda^2=0$

Hence, characteristic polynomial = $\lambda^3-\lambda^2=0$

b.We have to find the eigen value for given matrix

$\lambda^2(1-\lambda)=0$

Then , we get $\lambda=0,0,1-\lambda=0$

$\lambda=1$

Hence, real eigen values of for the matrix are 0,0 and 1.

c.Eigen space corresponding to eigen value 1 is the null space of matrix $A-I$

$E_1=N(A-I)$

$A-I=\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&-1\end{array}\right]$

Apply $R_1\rightarrow R_1+R_3$

$A-I=\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&0\end{array}\right]$

Now,(A-I)x=0[/tex]

Substitute the values then we get

$\left[\begin{array}{ccc}0&0&1\\1&-1&0\\0&0&0\end{array}\right]\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right]=0$

Then , we get $x_3=0$

And $x_1-x_2=0$

$x_1=x_2$

Null space N(A-I) consist of vectors

x= $\left[\begin{array}{ccc}x_1\\x_1\\0\end{array}\right]$

For any scalar $x_1$

$x=x_1\left[\begin{array}{ccc}1\\1\\0\end{array}\right]$

$E_1=N(A-I)=Span(\left[\begin{array}{ccc}1\\1\\0\end{array}\right]$

Hence, the basis of eigen vector corresponding to eigen value 1 is given by

$\left[\begin{array}{ccc}1\\1\\0\end{array}\right]$

Eigen space corresponding to 0 eigen value

$N(A-0I)=\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]$

$(A-0I)x=0$

$\left[\begin{array}{ccc}1&0&1\\1&0&0\\0&0&0\end{array}\right]\left[\begin{array}{ccc}x_1\\x_2\\x_3\end{array}\right]=0$

$\left[\begin{array}{ccc}x_1+x_3\\x_1\\0\end{array}\right]=0$

Then, $x_1+x_3=0$

$x_1=0$

Substitute $x_1=0$

Then, we get $x_3=0$

Therefore, the null space consist of vectors

$x=x_2=x_2\left[\begin{array}{ccc}0\\1\\0\end{array}\right]$

Therefore, the basis of eigen space corresponding to eigen value 0 is given by

$\left[\begin{array}{ccc}0\\1\\0\end{array}\right]$

5 0

3 years ago

Find 56,794 divided by 338. Write the quotient twice, once with the remainder as a fraction and one with an r.

PilotLPTM [1.2K]

169 r 86 would be the correct answer bc all u had to do was divide 56,794 by 338 and see what the forst few numbers were then multiply what u got which would have been 169 if u did it right and multiply that by 338 and 169X338=57,122 then u subtract that and u will get 86 so the correct answer would be 169 r 86!

7 0

3 years ago

Read 2 more answers

A farmer plants the same amount every day, adding up to 413 acres at the end of the year. If the year is 58 over, how many acres

puteri [66]

Using proportions, it is found that the farmer has planted 258 acres.

<h3>What is a proportion?</h3>

A proportion is a fraction of a total amount, and the measures are related using a rule of three.

He plants 413 acres during the entire year, hence, considering he plants an equal amount daily, and the year is 5/8 over, the amount he has planted is:

A = (5/8) x 413 = 258 acres.

More can be learned about proportions at brainly.com/question/24372153

#SPJ1

6 0

2 years ago