What is x(-14x + 9)?

Solving a word problem using a two-step med

stepladder [879]

Inequality is 6t ≤ 44 and Jim can rent a boat for 7.33 hrs or less

<u> Solution:</u>

Given that

Maximum amount Jim can spend to rent a boat = $34

Rental cost of boat for 1 hour = $6

Also Jim has a discount coupon for $8 off.

Need to determine possible number of hours Jim could rent a boat.

Let’s assume possible number of hours Jim could rent a boat be represented by variable "t"

Cost of renting boat for 1 hour = 6

So Cost of renting a boat for t hours = t x renting boat for 1 hour = t x 6 = 6t

Also Maximum amount Jim can spend to rent a boat = $34

As Jim has a discount coupon for $8 off, so Total amount Jim can spend to rent a boat = $ 34 + $ 8 = $ 44

So cost of renting a boat for t hours must be less that of equal to Total amount Jim can spend to rent a boat

=> 6t ≤ 44

On solving above equality for "t" we get ,

$\begin{array}{l}{t \leq \frac{44}{6}} \\\\ {=>\mathrm{t} \leq 7.3333 \mathrm{hrs}}\end{array}$

Hence inequality is 6t ≤ 44 and Jim can rent a boat for 7.33 hrs or less.

5 0

3 years ago

Select the correct answer.

Maurinko [17]

X^2 + 2x - 15
(x - 3) (x + 5)
B. (x - 3)

6 0

3 years ago

Read 2 more answers

Bet u can’t solve this

S_A_V [24]

Answer:

Step-by-step explanation:

Assuming you're solving for p:

$m=2^{-1} *2^p(2^p-1)$

Let $y=2^p$

Now we can re-write the equation with $y$ instead of $2^p$ .

$m=\frac{1}{2} y(y-1)$

$2m=y^2-y$

$y^2-y-2m=0$

Use the quadratic formula to get:

$y = \frac{1+\sqrt{1+8m} }{2}$

or

$y = \frac{1-\sqrt{1+8m} }{2}$

Therefore, using natural log and log rules:

$2^p = \frac{1+\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1+\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1+\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1+\sqrt{1+8m} }{2})}{ln(2)}$

or

$2^p = \frac{1-\sqrt{1+8m} }{2}$ , $ln(2^p)= ln(\frac{1-\sqrt{1+8m} }{2})$ , $pln(2) = ln(\frac{1-\sqrt{1+8m} }{2})$ , $p = \frac{ln(\frac{1-\sqrt{1+8m} }{2})}{ln(2)}$