Answer:
Step-by-step explanation:
Given a general quadratic formula given as ax²bx+c = 0
To generate the general formula to solve the quadratic equation, we can use the completing the square method as shown;
Step 1:
Bringing c to the other side
ax²+bx = -c
Dividing through by coefficient of x² which is 'a' will give:
x²+(b/a)x = -c/a
- Completing the square at the left hand side of the equation by adding the square of half the coefficient x i.e (b/2a)² and adding it to both sides of the equation we have:
x²+(b/a)x+(b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a+(b/2a)²
(x+b/2a)² = -c/a + b²/4a²
- Taking the square root of both sides
√(x+b/2a)² = ±√-c/a + b²/√4a²
x+b/2a = ±√(-4ac+b²)/√4a²
x+b/2a =±√b²-4ac/2a
- Taking b/2a to the other side
x = -b/2a±√√b²-4ac/2a
Taking the LCM:
x = {-b±√b²-4ac}/2a
This gives the vertex form with how it is used to Solve a quadratic equation.
First you must acknowledge that you are dealing with a line therefore you must write linear equation or linear function in this case.
Linear function has a form of,

Then calculate the slope <em>m</em> using the coordinates of two points. Let say <em>A(x1, y1)</em> and <em>B(x2, y2)</em>,

Now pick a point either <em>A</em> or <em>B</em> and insert coordinates of either one of them in the linear equation also insert the slope you just calculated, I will pick point <em>A</em>.

From here you solve the equation for n,

So you have slope <em>m</em> and variable <em>n</em> therefore you can write down the equation of the line,

Hope this helps.
r3t40
Answer:
4.66 (4 2/3, 14/3)
Step-by-step explanation:
Answer:
60
Step-by-step explanation:
b = the hypotenuse of a right angle triangle
a = the adjacent side.
R is being defined by the cosine
cos(R) = adjacent / hypotenuse
adjacent = 16* sqrt(2)
hypotenuse = 32*sqrt(2)
Cos(R) = 16*sqrt(2) / 32*sqrt(2) sqrt(2) cancels.
cos(R) = 1/2
R = cos-1(1/2)
R = 60 degrees.
Answer:
• x = 9
• y = 6√2
Step-by-step explanation:
The right triangles are all similar, so the ratios of hypotenuse to short side are the same:
27/x = x/3
x^2 = 81 . . . . . multiply by 3x
x = 9 . . . . . . . . take the square root
Then y can be found from the Pythagorean theorem:
x^2 = y^2 + 3^2
81 - 9 = y^2 = 72 . . . . . subtract 9
y = √72 = 6√2 . . . . . . .take the square root
The values of x and y are 9 and 6√2, respectively.