Given that Circle O is centered at (3,-2) and the circle passesthroughR(7,1),Thedistance between O and R is the radius (r).r=√(7−3)2(1−(−2))2=√25=5diameter =2⋅r=2⋅5=10.
Answer:
2
Step-by-step explanation:
Solve. To do so, change the division sign into a multiplication sign, and flip the second fraction:
(2/3)/(1/3) = (2/3) x (3/1)
Multiply across:
(2 * 3)/(3 * 1) = (6)/(3)
Simplify:
6/3 = 2
2 is your answer.
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Answer:
The correct answer is A) -19 1/2
Step-by-step explanation:
Use the rules of logarithms and the rules of exponents.
... ln(ab) = ln(a) + ln(b)
... e^ln(a) = a
... (a^b)·(a^c) = a^(b+c)
_____
1) Use the second rule and take the antilog.
... e^ln(x) = x = e^(5.6 + ln(7.5))
... x = (e^5.6)·(e^ln(7.5)) . . . . . . use the rule of exponents
... x = 7.5·e^5.6 . . . . . . . . . . . . use the second rule of logarithms
... x ≈ 2028.2 . . . . . . . . . . . . . use your calculator (could do this after the 1st step)
2) Similar to the previous problem, except base-10 logs are involved.
... x = 10^(5.6 -log(7.5)) . . . . . take the antilog. Could evaluate now.
... = (1/7.5)·10^5.6 . . . . . . . . . . of course, 10^(-log(7.5)) = 7.5^-1 = 1/7.5
... x ≈ 53,080.96
Since he’s already at -15, if he writes a check for 7 then he’s subtracting more from his account.
So, -15-7=-22
