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klemol [59]
2 years ago
7

Find the domain and the range of the relation. Determine whether the relation is a function.

Mathematics
1 answer:
luda_lava [24]2 years ago
6 0

Answer:

Domain = -3, 2, -8

Range = 1, 6, -6

Function? No

Step-by-step explanation:

Domain = x-values(no repeats)

Domain = -3, 2, -8

Range = y-values(no repeats)

Range = 1, 6, -6

Function?

No, the domain is repeating. Range can repeat but domain cannot

For more info about deciding if its a function or not, learn about the VLT

(vertical line test)

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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So probabaility for \mathrm{X}=1 is

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So expected frequency for X=1 is 0.3679^{*} 30=11.037 (or \left.11.04\right) .

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3 years ago
a box contains 20 blue marbes, 16 green marbles, and 14 red marbles. two marbles are selected at random. let 3 be the event that
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Answer:

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Step-by-step explanation:

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3 years ago
Help with Pre Calculus
marshall27 [118]

Answer:

The first option

Step-by-step explanation:

The domain of a rational function should be all real numbers except for when the denominator is equal to 0. To find when the denominator is equal to 0 you simply need to find the zeroes of the denominator... but in this case you can do that through factoring and using the quadratic equation.

So first step is going to be to factor out the GCF, which in this case is x. This gives you the equation. x(2x^2-x-15). So one of the zeroes is when x=0. Now to find the other two zeroes you can use the quadratic equation which is x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}\\\\. So to find the other zeroes you simply plug the values in. a=2, b=-1, c=-15

x=\frac{-(-1)\pm\sqrt{(-1)^2-4(2)(-15)}}{2(2)}\\\\x=\frac{1\pm\sqrt{1-4(2)(-15)}}{4}\\\\x=\frac{1\pm\sqrt{121)}}{4}\\\\x=\frac{1\pm11}{4}\\\\x=\frac{12}{4}\\x=3\\\\x=\frac{-10}{4}\\x=-\frac{5}{2}

4 0
2 years ago
WILL GIVE FIRST ANSWER BRAINLIEST
DedPeter [7]
My answer is D.(5, -2)
4 0
3 years ago
Read 2 more answers
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