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alexgriva [62]
3 years ago
9

An operations analyst counted the number of arrivals per minute at an ATM in each of 30 randomly chosen minutes. The results wer

e: 0, 3, 3, 2, 1, 0, 1, 0, 0, 1, 1, 1, 2, 1, 0, 1, 0, 1, 2, 1, 1, 2, 1, 0, 1, 2, 0, 1, 0, 1. For the Poisson goodness-of-fit test, what is the expected frequency of the data value X
Mathematics
1 answer:
liraira [26]3 years ago
8 0

Step-by-step explanation:

since Poisson distribution parameter is not given so we have to estimate it from the sample data. The average number of of arrivals per minute at an ATM is

\hat{\lambda}=\bar{x}=\frac{\sum x}{n}=\frac{30}{30}=1

So probabaility for \mathrm{X}=1 is

P(X=1)=\frac{e^{-\lambda} \lambda^{x}}{x !}=\frac{e^{-1} \cdot 1^{1}}{1 !}=0.3679

So expected frequency for X=1 is 0.3679^{*} 30=11.037 (or \left.11.04\right) .

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