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kiruha [24]
3 years ago
8

WILL GIVE FIRST ANSWER BRAINLIEST

Mathematics
2 answers:
koban [17]3 years ago
6 0

Answer: The correct option is (D) (5, -2).

Step-by-step explanation:  We are given to use the method of substitution to solve the following system of equations :

3x+7y=1~~~~~~~~~~~~~~~~~~~~~~~~~(i)\\\\y=x-7~~~~~~~~~~~~~~~~~~~~~~~~~~~~(ii)

Substituting the value of y from equation (ii) in equation (i), we get

3x+7y=1\\\\\Rightarrow 3x+7(x-7)=1\\\\\Rightarrow 3x+7x-49=1\\\\\Rightarrow 10x=50\\\\\Rightarrow x=\dfrac{50}{10}\\\\\Rightarrow x=5,

and from equation (ii) again, we get

y=x-7=5-7=-2.

Thus, the required solution is (x, y) = (5, -2).

Option (D) is CORRECT.

DedPeter [7]3 years ago
4 0
My answer is D.(5, -2)
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Find e^cos(2+3i) as a complex number expressed in Cartesian form.
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Answer:

The complex number e^{\cos(2+31)} = \exp(\cos(2+3i)) has Cartesian form

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Step-by-step explanation:

First, we need to recall the definition of \cos z when z is a complex number:

\cos z = \cos(x+iy) = \frac{e^{iz}+e^{-iz}}{2}.

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Now, recall the definition of the complex exponential:

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e^{-2i+3} = e^{3}(\cos 2-i\sin 2) (we use that \sin(-y)=-\sin y).

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\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2-i\sinh 3\sin 2\right)

\exp\left(\cos(2+3i)\right) = \exp\left(\cosh 3\cos 2\right)\left[ \cos(\sinh 3\sin 2)-i\sin(\sinh 3\sin 2)\right].

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