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Afina-wow [57]
2 years ago
13

Convert to the given unit Quarts and cups

Mathematics
1 answer:
Gennadij [26K]2 years ago
8 0

Answer: 20

Step-by-step explanation:

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PLEASE HELP!!<br> It’s asking for the measure of Arc KL in degrees
barxatty [35]

Answer:

30 degrees

Step-by-step explanation:

5 0
3 years ago
An angle measures 32° more than the measure of its complementary angle. What is the measure of each angle?
Leviafan [203]

Answer:

29° ; 61°

Step-by-step explanation:

Let one angle  = x°

Other angle = (x + 32)°

x + x + 32 = 90   {given they are complementary}

2x + 32 = 90

2x = 90 -32

2x = 58

x = 58/2

x = 29

One angle  = 29°

Other angle = 29 + 32 = 61°            

3 0
3 years ago
What is the total surface area of the rectangular<br> prism represented by this net?
dedylja [7]

Answer:

Total surface area of the rectangular  prism is 150.88 cm^2

Step-by-step explanation:

area of base = area of top

area of base = 5 x 3.1 = 15.5 cm^2

Area of small lateral surface having dimensions 3.1 cm x 7.4 cm is

=3.1 x 7.4 = 22.94 cm^2

Area of big lateral surface having dimensions 5 cm x 7.4 cm is

=5 x 7.4 = 37 cm^2

Total area of prism = 2 x 15.5 + 2 x 22.94 + 2 x 37 = 150.88 cm^2

total surface area of the rectangular  prism is 150.88 cm^2

7 0
3 years ago
Read 2 more answers
PLZZZZ HELPPPPPPP!!!!
Vladimir79 [104]

Answer: The height of the building is 50.75 feet.

Step-by-step explanation:

The ratio between the height of the object and the casted shadow must be equal for all the objects, as the angle at which the source if light impacts them is the same.

For the person, we know that it is 5.8ft tall, and the shadow is 3.2ft long.

The ratio will be: 5.8ft/3.2ft = 1.8125

Now, if H is the height of the building, and the shadow that the building casts is 28ft, we must have:

H/28ft = 1.8125

Now we can solve this for H.

H = 1.8125*28ft = 50.75 ft

Then the height of the building is 50.75 feet.

3 0
3 years ago
Twice a number is less than 15 (turn into inequality)
velikii [3]

x \times 2
3 0
3 years ago
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