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Allisa [31]
3 years ago
11

10z - XY X=2,y=4 and z=-5 Show work

Mathematics
1 answer:
Alex787 [66]3 years ago
8 0

Answer: 10 x -5 - 2 x 4 = -58

Step-by-step explanation: the z from the 10 z becomes -5 and the x becomes 2 and the y becomes 4 simply just answer it

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Find the equation of a line perpendicular to x−5y=4 that contains the point (−1,2). Write the equation in slope-intercept form
Alexandra [31]

Answer:

y = - 5x - 3

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Given

x - 5y = 4 ( subtract x from both sides )

- 5y = - x + 4 ( divide the terms by - 5 )

y = \frac{1}{5} x - \frac{4}{5} ← in slope- intercept form

with slope m = \frac{1}{5}

Given a line with slope m then the slope of a line perpendicular to it is

m_{perpendicular} = - \frac{1}{m} = - \frac{1}{\frac{1}{5} } = - 5 , then

y = - 5x + c ← is the partial equation

To find c substitute (- 1, 2) into the partial equation

2 = 5 + c ⇒ c = 2 - 5 = - 3

y = - 5x - 3 ← equation of perpendicular line

5 0
3 years ago
Emily is entering a bicycle race for charity. Her mother pledges $0.90 for every 0.75 mile she bikes. If Emily bikes 15 miles, h
Kay [80]
18 because 15÷0.75 is 20. 20×.90 is 18. -JZ
5 0
3 years ago
Please help me with the last two in the pic
lisabon 2012 [21]
10. ×3+2
11. couldnt figure it out sorry
3 0
3 years ago
Read 2 more answers
Gas is escaping from a spherical balloon at the rate of 12 ft3/hr. At what rate (in feet per hour) is the radius of the balloon
bija089 [108]

Answer:

This is the rate at which the radius of the balloon is changing when the volume is 300 ft^3 \frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \:\frac{ft}{h}  \approx -0.05537 \:\frac{ft}{h}

Step-by-step explanation:

Let r be the radius and V the volume.

We know that the gas is escaping from a spherical balloon at the rate of \frac{dV}{dt}=-12\:\frac{ft^3}{h} because the volume is decreasing, and we want to find \frac{dr}{dt}

The two variables are related by the equation

V=\frac{4}{3}\pi r^3

taking the derivative of the equation, we get

\frac{d}{dt}V=\frac{d}{dt}(\frac{4}{3}\pi r^3)\\\\\frac{dV}{dt}=\frac{4}{3}\pi (3r^2)\frac{dr}{dt} \\\\\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}

With the help of the formula for the volume of a sphere and the information given, we find r  

V=\frac{4}{3}\pi r^3\\\\300=\frac{4}{3}\pi r^3\\\\r^3=\frac{225}{\pi }\\\\r=\sqrt[3]{\frac{225}{\pi }}

Substitute the values we know and solve for \frac{dr}{dt}

\frac{dV}{dt}=4\pi r^2 \frac{dr}{dt}\\\\\frac{dr}{dt}=\frac{\frac{dV}{dt}}{4\pi r^2} \\\\\frac{dr}{dt}=-\frac{12}{4\pi (\sqrt[3]{\frac{225}{\pi }})^2} \\\\\frac{dr}{dt}=-\frac{3}{\pi \left(\sqrt[3]{\frac{225}{\pi }}\right)^2}\\\\\frac{dr}{dt}=-\frac{3}{\pi \frac{225^{\frac{2}{3}}}{\pi ^{\frac{2}{3}}}}\\\\\frac{dr}{dt}=-\frac{3}{225^{\frac{2}{3}}\pi ^{\frac{1}{3}}} \approx -0.05537 \:\frac{ft}{h}

7 0
4 years ago
Now answer the question:
Viktor [21]
X=3
Y=5
0.30 x 5 = 1.5
1.50 x 3 = 4.5
1.5 + 4.5 = 6
5 0
2 years ago
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