Conditional probablility P(A/B) = P(A and B) / P(B). Here, A is sum of two dice being greater than or equal to 9 and B is at least one of the dice showing 6. Number of ways two dice faces can sum up to 9 = (3, 6), (4, 5), (4, 6), (5, 4), (5, 5), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 10 ways. Number of ways that at least one of the dice must show 6 = (1, 6), (2, 6), (3, 6), (4, 6), (5, 6), (6, 6), (6, 5), (6, 4), (6, 3), (6, 2), (6, 1) = 11 ways. Number of ways of rolling a number greater than or equal to 9 and at least one of the dice showing 6 = (3, 6), (4, 6), (5, 6), (6, 3), (6, 4), (6, 5), (6, 6) = 7 ways. Probability of rolling a number greater than or equal to 9 given that at least one of the dice must show a 6 = 7 / 11
A stem and leaf plot shows sets of two digit numbers, by separating the ten’s place and the one’s place. On the left is the different ten’s values, while on the right next to each of the values on the left is the one’s values that associate with each of the ten’s values. This means that the numbers in this set of data are 32, 47, 51, 55, 55, 55, 58, 64, and so on. From there, you can use that knowledge to figure out how many scores were above 60.
The terms that are above 60 are 64, 65, 73, 74, 77, 87, 88, 91, 93, 93, 97, 99, and 99, for a total of 13 of the 20 scores being above 60.
Answer:
<em>17/2, 8.8 with bar on right 8, |-9|, sqrt(82)</em>
Step-by-step explanation:
sqrt(82) = 9.05538...
17/2 = 8.5
8.8 with bar on right 8 = 8.8888888...
|-9| = 9
In order from least to greatest: 17/2, 8.8 with bar on right 8, |-9|, sqrt(82)
