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3 years ago

Can anyone help me with these this problem. Show your work

Mathematics

2 answers:

nignag [31]3 years ago

8 0

the answer to your question is 133 mm

Finger [1]3 years ago

7 0

the answer to your question is 13 mm

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If you add Natalie's age and Fred's age, the result is 42. If you add Fred's age to 3 times

Alla [95]

Answer:

N+F=42 & F+3N=70 System Solved: Natalie is 14 and Fred is 28

Step-by-step explanation:

Using variables N=natalies age and F=Freds age

N+F=42 ----> N=42-F (take this and plug it into the other equation)

F+3N=70 so F+3(42-F)=70 [simplify] F+126-3F=70 [further simplify]

-2F=-56 [divide -56 by -2] F=28 [then plug this number into the orig. equation]

So N+28=42 or N=14.

5 0

3 years ago

<img src="https://tex.z-dn.net/?f=%20%5Cfrac%7B%20%5Csqrt%7B-4%7D%20%7D%7B%283%2B1%29-%282%2B3i%29%7D%20" id="TexFormula1" title

frozen [14]

$\sqrt{-4}$ can also be written as 2i
where i = √-1

$\frac{2i}{4-2-3i} = \frac{2i}{2-3i}$

Rationalizing denominator,

$\frac{2i(2+3i)}{(2-3i)(2+3i)} = \frac{4i-6}{4+9} = \frac{4i-6}{13}$

8 0

3 years ago

Look at this expression.

Soloha48 [4]

Answer:

c 18

Step-by-step explanation:

Idid thsi in Kahn academy and got it correctly

4 0

2 years ago

Find the Value of X Please

Yanka [14]

Answer:

x=6

Step-by-step explanation:

3x-5=2x+1

x-5=1

x=6

6 0

3 years ago

Those 2 questions I need help with . find sec θ and tanθ

Zielflug [23.3K]

STEP - BY - STEP EXPLANATION

What to find?

The the value of secθ.

Given:

(4, 3)

⇒(x, y) = (4, 3)

Step 1

Draw a sketch.

Step 2

Substitute the values into the trig. ratio formula below.

$tan\theta=\frac{opposite}{adjacent}$

From the sketch above, opposite = 3 and adjacent = 4

$tan\theta=\frac{3}{4}$

Step 3

Find the value of the hypotenuse side using Pythagoras theorem.

let h be the hypotenuse side.

$\begin{gathered} h^2=4^2+3^2 \\ \\ =16+9 \\ \\ =25 \\ \\ h=5 \end{gathered}$

Hence, hypotenuse = 5

Step 4

Substitute the values into the formula below:

$\begin{gathered} cos\theta=\frac{adjacent}{hypotenuse} \\ \\ =\frac{4}{5} \end{gathered}$

But,

$sec\theta=\frac{1}{cos\theta}=\frac{1}{\frac{4}{5}}=\frac{5}{4}$

ANSWER

secθ= 5/4

tanθ=3/4

7 0

1 year ago