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3 years ago

Math mAThHh hahaha MMAMAEMEAAT math ..

Mathematics

2 answers:

Nat2105 [25]3 years ago

3 0

Answer:

$3r+8$

Explanation:

mAtHhhh

Montano1993 [528]3 years ago

3 0

I wish I knew, but I don't sorry :(

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X/-9 +9=8 please help me

nekit [7.7K]

X = 9 X/-9 +9=8 9<span>/-9 +9=8 </span>

6 0

3 years ago

Read 2 more answers

R (-3,1) and S (-1,3) are points on a circle. If RS is a diameter, find the equation of the circle.

ELEN [110]

Answer:

$\sf (x+2)^2+(y-2)^2=2$

Step-by-step explanation:

If RS is the diameter of the circle, then the midpoint of RS will be the center of the circle.

$\sf midpoint=\left(\dfrac{x_s-x_r}{2}+x_r,\dfrac{y_s-y_r}{2}+y_r \right)$

$\sf =\left(\dfrac{-1-(-3)}{2}+(-3),\dfrac{3-1}{2}+1 \right)$

$\sf =(-2, 2)$

Equation of a circle: $\sf (x-h)^2+(y-k)^2=r^2$

(where (h, k) is the center and r is the radius)

Substituting found center (-2, 2) into the equation of a circle:

$\sf \implies (x-(-2))^2+(y-2)^2=r^2$

$\sf \implies (x+2)^2+(y-2)^2=r^2$

To find $\sf r^2$ , simply substitute one of the points into the equation and solve:

$\sf \implies (-3+2)^2+(1-2)^2=r^2$

$\sf \implies 1+1=r^2$

$\sf \implies r^2=2$

Therefore, the equation of the circle is:

$\sf (x+2)^2+(y-2)^2=2$

4 0

3 years ago

Tina’s little brother had 25 liters of water in his wading pool and splashed 1/5 of the water out. Tina then added 7 liters of w

Shkiper50 [21]

Amount of water after splash = 25(4/5) = 20L

Amount of water after Tina adds water = 20L + 7L = 27L

7 0

3 years ago

Read 2 more answers

Roger has two golden retrievers, sadie and buddy, buddy weighs 14 pounds more than sadie, if their total wight is 136 pounds, ho

Vlad1618 [11]

Answer:

A) buddy = sadie + 14

B) buddy + sadie = 136

A) buddy -sadie = 14

Adding equations A & B

2 * buddy = 150

buddy = 75 pounds

sadie = 61 pounds

Step-by-step explanation:

6 0

3 years ago

Nielsen ratings are based on televisions in 50005000 households. Nielsen estimates that 12 comma 00012,000 people live in these

avanturin [10]

Answer:

We are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%

Step-by-step explanation:

-From the given information, $\hat p=0.65$ .

-We calculate the confidence interval using this value at 95% confidence level:

$CI=\hat p\pm z \sqrt{\frac{\hat p(1-\hat p)}{n}}\\\\\\=0.65\pm 1.96\times \sqrt{\frac{0.65\times 0.35}{12000}}\\\\\\=0.65\pm 0.0085\\\\\\=[0.6415,0.6585]$

So, the 95% confidence interval is (0.6515,0.6585).

Hence, we are 95% confident that the true proportion of TV audience is between 65.15% and 65.85%.

6 0

3 years ago