For what visible wavelengths of light do the reflected waves interfere constructively? The range of wavelength of visible light
1 answer:
Answer:
None of the wavelength is in the visible range
Explanation:
Constructive interference of the reflected waves for different wavelengths can be estimated using:
λ = 2nd/m
where m is 1,2,3, ...
Therefore:
m=1, λ = 750 nm
m=2, λ = 750/2 = 375 nm
The limits of eye's sensitivity is between 430 nm and 690 nm. Beyond this range, the eye's sensitivity drops to approximately 1% of its maximum value.
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Answer:
The angular speed is 0.13 rev/s
Explanation:
From the formula
Where is the torque
is the moment of inertia
is the angular acceleration
But, the angular acceleration is given by
Where is the angular speed
and is time
Then, we can write that
Hence,
Now, to determine the angular speed, we first determine the Torque and the moment of inertia
.
Here, The torque is given by,
Where r is the radius
and F is the force
From the question
r = 3.00 m
F = 195 N
∴
Nm
For the moment of inertia,
The moment of inertia of the solid disk is given by
Where M is the mass and
R is the radius
∴
kgm²
From the question, time t = 2.05 s.
Putting the values into the equation,
rad/s
Now, we will convert from rad/s to rev/s. To do that, we will divide our answer by 2π
0.82 rad/s = 0.82/2π rev/s
= 0.13 rev/s
Hence, the angular speed is 0.13 rev/s,