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anastassius [24]
3 years ago
14

In deep space, there is very little friction. Once they launch a probe into deep space, where there are no external forces actin

g on it, scientists shut the probe’s engines off because the scientists want the probe to stop immediately. speed up. slow down. move at constant velocity.
Physics
2 answers:
Charra [1.4K]3 years ago
5 0

Answer:

move at constant velocity.

Explanation:

Newton's first law (also known as law of inertia) states that:

"when the net force acting on an object is zero, the object will keep its state of rest or if it is moving, it will continue moving at constant velocity".

In the case of the probe, friction in deep space is negligible, therefore when the engine is shut down, there are no more forces acting on the probe: the net force therefore will be zero, so the probe will move at constant velocity.

melamori03 [73]3 years ago
5 0
<span>move at constant velocity. 



</span>
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An electron has a charge of 1.602 X 10-19.coulomb. When two electrons are separated by 1.2 X 10-9m, what force will they exert o
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Answer:

The force they will exert on each other is 1.6*10⁻¹⁰ N

Explanation:

The electromagnetic force is the interaction that occurs between bodies that have an electric charge. When the charges are at rest, the interaction between them is called the electrostatic force. Depending on the sign of the interacting charges, the electrostatic force can be attractive or repulsive. The electrostatic interaction between charges of the same sign is repulsive, while the interaction between charges of the opposite sign is attractive.

Coulomb's law is used to calculate the electric force acting between two charges at rest. This force depends on the distance "r" between the electrons and the charge of both.

Coulomb's law is represented by:

F=k*\frac{q1*q2}{r^{2} }

where:

  • F = electric force of attraction or repulsion in Newtons (N). Like charges repel and opposite charges attract.
  • k = is the Coulomb constant or electrical constant of proportionality.
  • q = value of the electric charges measured in Coulomb (C).
  • r = distance that separates the charges and that is measured in meters (m).

In this case:

  • k= 9*10⁹ \frac{N*m^{2} }{C^{2} }
  • q1= 1.602*10⁻¹⁹ C
  • q2= 1.602*10⁻¹⁹ C
  • r= 1.2*10⁻⁹ m

Replacing:

F=9*10^{9} \frac{N*m^{2} }{C^{2} }*\frac{1.602*10^{-19} C*1.602*10^{-19} C}{(1.2*10^{-9} )^{2} }

and solving you get:

F=1.6*10⁻¹⁰ N

<u><em>The force they will exert on each other is 1.6*10⁻¹⁰ N</em></u>

3 0
3 years ago
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