it could cause vaginal itching.
Answer:
Seaweeds, shrimps, salmon
Explanation:
The rapid increase in the human population day by day has led to the increased usage of marine plants and animals. Due to this, the population f some marine plants and animals is declining to threatening levels.
To overcome his problem, scientists have devised the method of mariculture. This technique involves raising aquatic plants and animals in artificial lakes or ponds containing salty water just like in the oceans.
Some of these plants and animals are:
- Sea weeds: People might think that they do not consume sea weeds but it is actually present in most of our daily use products like toothpaste, ice creams and even in some automobiles. Many people from the world consume sea weeds as food. Hence, they are being raised in maricultures.
- Shrimps: Shrimps are favourite sea food among many people belonging to different areas. Hence, there population is declining due to which they need to be raised artificially.
- Salmon: The salmon is a kind of fish common to almost every nation. Hence, to meet the demands of people they need to be produced in maricultures.
Answer:
setting regulations for trains carrying cargo
Explanation:
USMA is the United States Military Academy in the West point. This academy provides a bachelor of science degree along with a cadet's performance in military and athletic activities.
USMA control diferrent functions in West Point and one of them is setting regulations for trains carrying cargo. USMA controls the department of defense and is responsible for making rules and regulation related to the trains carrying cargo.
Hence, the correct answer is "setting regulations for trains carrying cargo".
Really, there are multiple questions all rolled into one.I will try to answer them patiently and systematically.
First summarize data.
A. Neither Olivia nor Marcus have freckles (recessive, ff)
B. Both are heterozygous for the hairline trait (dominant Ww)
C. Neither Marcus nor Olivia can roll their tongues (rr).
D. All four children have dimples (dominant Dx)
E. Both Olivia and Marcus are EE (unattached earlobe trait).
F. Marcus can not detect the bitter taste (pp for PTC gene)Olivia has been found to be able to detect the bitter taste, but she is heterozygous for the trait. (Pp for PTC gene)
A. Freckles, F (Dominant)
"Neither Olivia nor Marcus have freckles" =>
both have genotype ff.
None of the children have freckles (i.e. P(F)=0% for freckles in all children)
B. Widow's Peak, W (dominant)
"Both are heterozygous for the hairline trait"
So both have genotype Ww.
Punnett square
W w
W WW Ww
w Ww ww
Since W is a dominant trait, only ww (25%) will have straight hairline, 75% will inherit the widow's peak.
50% of the children will be homozygous (Ww).
C. Rolling tongues, R (dominant)
"Neither Marcus nor Olivia can roll their tongues"
means that both are homozygous recessive, with genotype rr.As in freckles, all children will have genotype rr, so none of them will roll their tongues.
None will be heterozygous. The whole family's genotype is rr.
D. Dimples, D (dominant)
"D. All four children have dimples"
implies that all children have genotype DD or Dd.
It is likely that at least one parent has genotype DD in order to have 100% of children have DD or Dd.Here are some possibilities
Case 1: DD + DD (both homoozygous dominant)
D D
D DD DD
D DD DD
Phenotype: 100% have dimples
Case 2: DD + Dd (one homoozygous dominant, and other heterozygous)
D d
D DD Dd
D DD Dd
Phenotype: 100% have dimples
Case 3: DD + dd (one homoozygous dominant, and other homozygous recessive)
D D
D DD DD
d Dd Dd
Phenotype: 100% have dimples
Case 4: Dd + Dd (both heterozygous)
D d
D DD Dd
d Dd dd
Phenotype: 75% have dimples, 25 do not.Note: all 4 children could have dimples, with probability 31.6%
Case 5: Dd + dd (Heterozygous + homozygous recessive)
D d
d Dd dd
d Dd dd
Phenotype: 50% have dimples, 50 do not.Note: All four children could have dimples, with probability 6.25%.
Case 6: dd + dd (Both homozygous recessive)
D d
d dd dd
d dd dd
Phenotype: all children have no dimples.
Conclusion:Likely genotypes of parents: DD+DD, DD+Dd, DD+dd
Possible genotypes of parents: Dd+Dd, Dd+dd
Impossible genotype of parents: dd+dd
Therefore we know with certainty that at least one of the parents has dimples.
E. Unattached Earlobe trait, E (dominant)
"Both Olivia and Marcus are EE"
(i.e. unattached earlobe trait).
This means that the whole family will have genotype EE, i.e. all are homozygous dominant, and have unattached earlobes.
F. Bitter taste, P (incomplete dominance)
"Marcus can not detect the bitter taste (pp for PTC gene)
Olivia has been found to be able to detect the bitter taste, but she is heterozygous for the trait. (Pp)"
P p
p Pp pp
p Pp pp
Probability for each single child being able to taste the ptc paper is 1/2.
Probability for all children being able to taste the ptc paper is (1/2)^4=1/16.
If Violet cannot taste the ptc paper, her genotype is pp.
We do not know for sure how many of the children can taste the ptc paper.
The most like situation is only half of them can taste, so do the parents. Therefore, half of the family can taste the ptc paper.
Finally, as to "please answer it correctly", I believe I did. :)
