Jack's school is selling tickets to a spring musical. On the first day of ticket sales the school sold

rosa correctly solved 275 divided by 5.enter numbers in boxes to show the equations she could use to solve the problem

kifflom [539]

Answer:

The first step would be to look at the first two numbers (which is 27) and estimate which <u>multiple</u> of 5 is closest and <u>below</u> 27.

5*5 = 25

So once she got 25, she will need to subtract 27-25, which will give her 2. REMEMBER: 5 is the first number of the quotient.

Now, she will need to drag the last digit left of 275 (which is 5) to the remainder 2 and think what multiple of 5 will give her the answer 25.

Again, 5*5 = 25

Once again, her numbers on the quotient will be 55. That's the answer.

6 0

2 years ago

If you had carried out the algebra using variables before plugging numbers into your expressions, you would have found that (vf)

SashulF [63]

Answer:

Step-by-step explanation:

Volt is energy per electric charge

$1V=1J/C$

and the energy units in terms of meters, seconds and kilograms are:

$1J= 1kg\frac{m^{2}}{s^{2}}$

So the unit of volt is

$1V= kg \frac{m^{2}}{Cs^{2}}$

So the velocity expression (it can not be read completly) but i guess that it could be as follows

$vf_{a} = -2\sqrt{\frac{q_{a}\Delta V}{m_{a}}}$

So the unit analysis would be

$vf_{a} = \sqrt{\frac{C kg\frac{m^{2}}{Cs^{2}}}{kg}}}$

note that the coulomb unit of numerator is cancelled from the denominator. The same occurs for kg unit.

$vf_{a} = \sqrt{\frac{m^{2}}{s^{2}}}$

Applying square root

$vf_{a} = \frac{m}{s}$

7 0

3 years ago

Please tell me what this is

Harlamova29_29 [7]

Answer:7.2+z=10

Step-by-step explanation:if I am right you just have to do the equacion

4 0

2 years ago

F(x)=4x^3+Ax^2+8x-1 and f(2)=1

I am Lyosha [343]

The answer for A is A=-11.5

4 0

3 years ago

Find the indefinite integrals, if possible, using the formulas and techniques you have studied so far in the text.(a) 11 x4 dxTh

hoa [83]

Answer:

a) This integral can be evaluated using the basic integration rules. $\int 11x^{4}dx = \frac{11}{5} x^{5}+C$

b) This integral can be evaluated using the basic integration rules. $\int 8x^{1}x^{4}dx=\frac{4}{3}x^{6}+C$

c) This integral can be evaluated using the basic integration rules. $\int 3x^{31}x^{4}dx=\frac{x^{36}}{12}+C$

Step-by-step explanation:

a) $\int 11x^{4}dx$

In order to solve this problem, we can directly make use of the power rule of integration, which looks like this:

$\int kx^{n}=k\frac{x^{n+1}}{n+1}+C$

so in this case we would get:

$\int 11x^{4}dx=11 \frac{x^{4+1}}{4+1}+C$

$\int 11x^{4}dx=11 \frac{x^{5}}{5}+C$

b) $\int 8x^{1}x^{4}dx$

In order to solve this problem we just need to use some algebra to simplify it. By using power rules, we get that:

$\int 8x^{1}x^{4}dx=\int 8x^{1+4}dx=\int 8x^{5}dx$

So we can now use the power rule of integration:

$\int 8x^{5}dx=\frac{8}{5+1}x^{5+1}+C$

$\int 8x^{5}dx=\frac{8}{6}x^{6}+C$

$\int 8x^{5}dx=\frac{4}{3}x^{6}+C$

c) The same applies to this problem:

$\int 3x^{31}x^{4}dx=\int 3x^{31+4}dx=\int 3x^{35}dx$

and now we can use the power rule of integration:

$\int 3x^{35}dx=\frac{3x^{35+1}}{35+1}+C$

$\int 3x^{35}dx=\frac{3x^{36}}{36}+C$

$\int 3x^{35}dx=\frac{x^{36}}{12}+C$

6 0

2 years ago