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r-ruslan [8.4K]
3 years ago
5

Lim x tends to a now find x^1/3-a^1/3/x^1/2-a^1/2

Mathematics
1 answer:
blagie [28]3 years ago
4 0

Answer: \frac{a}{3}-\frac{2}{3}-\frac{a}{2}

Step-by-step explanation:

\lim _{x\to \:a}\left(\frac{x^1}{3}-\frac{\frac{a^1}{3}}{\frac{x^1}{2}}-\frac{a^1}{2}\right)

=\frac{a^1}{3}-\frac{\frac{a^1}{3}}{\frac{a^1}{2}}-\frac{a^1}{2}

=\frac{a}{3}-\frac{2}{3}-\frac{a}{2}

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