The number of ways, in which 3 fives can be picked out of 4 available fives would be 4C3. The number of ways in which 2 non-five cards can be picked out of the 48 available non-five cards would be 48C2.

$4C3=\frac{4!}{3!(4-3)!}=\frac{4*3!}{3!*1}=4$

$48C2=\frac{48!}{2!(48-2)!}=\frac{48*47*46!}{2*1*46!}=24*47=1128$

We can choose exactly three fives from five-card hands in $4C3*48C3$ ways.

$4C3*48C3=4*1128=4512$

Therefore, 4512 five card hands contain exactly three fives.

4 0

3 years ago

Logan can read at a rate of 2/3 page per minute. At that rate, how many pages can he read in 2 hours?

Anon25 [30]

Answer:

240- 360

Step-by-step explanation:

You have to find out how many minutes in an hour which is 60. Then multiply it by 2 for 2 hours to get 120. Then you multiply 2x120 to get 240. Then you multiply 3x120 to get 360.

I'm not sure if this is correct but this is how I would go about it. :)

7 0

3 years ago

19x+rx=-37x+w what does x equal

enyata [817]

Factor the left side:

x (19+ r)= -37 + w
x= (-37 + w) / (19 +r)

5 0

3 years ago