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2 years ago

14

a store has 2 boxes of markers. Each box holds 5 packs of markers. There are 8 markets in each pack. How many markers are in the

re in all?

1 answer:

Katyanochek1 [597]2 years ago

4 0

Multiply:

2 boxes x 5 packs each = 10 total packs

10 packs x 8 markers per pack = 80 total markers

Any: 80 markers

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What is the correct order of the numbers from least to greatest. 1/2, 0.6, 6%, 6/5

Anton [14]

Answer:

6%, 1/2, 0.6, 6/5

Step-by-step explanation:

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2 years ago

Read 2 more answers

Please help!!!!! thank u!!

Naddika [18.5K]

Set each piece = to 56, assuming that the 2 variables for which you are not solving are each equal to 0.

7x -2(0)-14(0) = 56
7x=56 (divide each side by 7)
X = ?
(__, 0, 0)

7(0) - 2y - 14 (0) = 56
-2y = 56 (divide each side by -2)
Y= ?
(0, __ , 0)

7(0) - 2(0) - 14z = 56
-14z = 56 (divide each side by -14)
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2 years ago

NASA is conducting an experiment to find out the fraction of people who black out at G forces greater than 6. In an earlier stud

SSSSS [86.1K]

Answer:

The large sample n = 190.44≅190

The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

<u>Step-by-step explanation</u>:

Given population proportion was estimated to be 0.3

p = 0.3

Given maximum of error E = 0.04

we know that maximum error

$M.E = \frac{Z_{\alpha } \sqrt{p(1-p)} }{\sqrt{n} }$

The 85% confidence level $z_{\alpha } = 1.44$

$\sqrt{n} = \frac{Z_{\alpha } \sqrt{p(1-p)} }{m.E}$

$\sqrt{n} = \frac{1.44X\sqrt{0.3(1-0.3} }{0.04}$

now calculation , we get

√n=13.80

now squaring on both sides n = 190.44

large sample n = 190.44≅190

<u>Conclusion</u>:-

Hence The large sample would be required in order to estimate the fraction of people who black out at 6 or more Gs at the 85% confidence level with an error of at most 0.04 is n = 190.44

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2 years ago

Which of the following shows the polynomial 3x^3 - 5x + x^7 + 9 + 4x^11 written in descending order?

alina1380 [7]

Answer:

4x^11+x^7+3x^3-5x+9

Its highest to lower based on the exponential number

our exponential numbers are: 3, 1, 7,0,11 putting those from highest to lowers would put them: 4x^11+x^7+3x^3-5x+9

7 0

1 year ago

A circle is growing so that the radius is increasing at the rate of 3 cm/min. How fast is the area of the circle changing at the

Naya [18.7K]

Answer:

The area is growing at a rate of $\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

Step-by-step explanation:

<em>Notice that this problem requires the use of implicit differentiation in related rates (some some calculus concepts to be understood), and not all middle school students cover such.</em>

We identify that the info given on the increasing rate of the circle's radius is 3 $\frac{cm}{min}$ and we identify such as the following differential rate:

$\frac{dr}{dt} = 3\,\frac{cm}{min}$

Our unknown is the rate at which the area (A) of the circle is growing under these circumstances,that is, we need to find $\frac{dA}{dt}$ .

So we look into a formula for the area (A) of a circle in terms of its radius (r), so as to have a way of connecting both quantities (A and r):

$A=\pi\,r^2$

We now apply the derivative operator with respect to time ( $\frac{d}{dt}$ ) to this equation, and use chain rule as we find the quadratic form of the radius:

$\frac{d}{dt} [A=\pi\,r^2]\\\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}$

Now we replace the known values of the rate at which the radius is growing ( $\frac{dr}{dt} = 3\,\frac{cm}{min}$ ), and also the value of the radius (r = 12 cm) at which we need to find he specific rate of change for the area :

$\frac{dA}{dt} =\pi\,*2*r*\frac{dr}{dt}\\\frac{dA}{dt} =\pi\,*2*(12\,cm)*(3\,\frac{cm}{min}) \\\frac{dA}{dt} =226.19467 \,\frac{cm^2}{min}\\$

which we can round to one decimal place as:

$\frac{dA}{dt} =226.2 \,\frac{cm^2}{min}$

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3 years ago