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Kipish [7]
1 year ago
5

What is the expected value for the following probability distribution?

Mathematics
1 answer:
dolphi86 [110]1 year ago
5 0

To calculate the expected value of our dataset, first we need to find the missing probability. The sum of the probabilities of all outcomes must add up to 1

\sum P(X)=1

Therefore, 1 minus all the other probability values is going to be P(2).

1-(0.04+0.05+0.2+0.1)=1-0.75=0.25

The expected value is given by the sum of every value of the dataset multiplied by its respective probability

E[X\rbrack=\sum P(x_i)x_i

Using this formula in our problem, we have:

\begin{gathered} E[X\rbrack=\sum_{i\mathop{=}1}^5P_i(x_i)x_i \\ =(0.4)\times(0)+(0.05)\times(1)+(0.25)\times(2)+(0.2)\times(3)+(0.1)\times(4) \\ =0+0.05+0.5+0.6+0.4 \\ =1.55 \end{gathered}

The expected value of this dataset is 1.55.

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A bag contains 5 red marbles, 3 white marbles, and 4 blue marbles. what is the probability of randomly selecting a red marble, s
Dennis_Churaev [7]
Total number of marbles=5+3+4=12
Probability of picking a red marble =5/12
5 0
3 years ago
I need help on 1-6 and If you can, can you explain how to do these? I'm not entirely sure how to.
gayaneshka [121]
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2. First, the diameter (d) is 12 so to get the radius (r), divide 12 by 2 and you should get 6. Then use c=2pi(r) for circumference and a=pi(r)^2 for area to solve.

3. To get the area of the semicircle, divide 16 by 2 to get the radius (r), plug it into a=pi(r)^2, and divide the answer you get for a by 2. To get the area of the triangle, use a=1/2bh, plugging in 16 for b and 10 for h. Finally, add your two answers (the a's from the semicircle and triangle problems).

4. Multiply 20 by 5.5 to get the area of the triangle. Then multiply 4.5 by 20 to get the area of the parallelogram and add your two quotients.

5. Use a=1/2bh and plug in 4 for b and 3 for h and solve. Then multiply the quotient by 10 and there's your volume. To find the surface area, solve SA=(10×4)+(10×3)+(10×5)+12. All I did there was find the area of all the sides and added them together.

6. To find the triangle's volume, use a=1/2bh (b=4, h=1.5) and then multiply the quotient of that by 2.5. To find the rectangle's volume, use v=lwh (l=4, w=2.5, h=2) and solve. Finally, add the triangle's volume and the rectangle's volume to get the total volume. To get its surface area, start with the rectangle. Find the areas of all the sides and add them together but then subtract the 2.5×4 rectangle as it is not on the surface. It should look like this: SA=2(4×2)+2(2.5×2)+10. Again, all I did was find the areas of all the rectangle's sides on the surface and added them. Next, find the triangle's areas on the surface and it should look like this: SA=2(1.5×4)+2(2.5×2.5). Finally, add both values of SA from the triangle and rectangle and there's your surface area.
7 0
3 years ago
X + y = –4<br> y = 3x + 16
babymother [125]
If
x+y=-4
y-3x=16 or we cn write as
   x+y=-4
-3x+y=16
i multiply the first equation by 3
3x+3y=-12
-3x+ y=16
4y=4
y=1
x+1=-4
x=-5

6 0
3 years ago
Read 2 more answers
If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then what is the pr
andreyandreev [35.5K]

If the probability of observing at least one car on a highway during any 20-minute time interval is 609/625, then the probability of observing at least one car during any 5-minute time interval is 609/2500

Given The probability of observing at least one car on a highway during any 20 minute time interval is 609/625.

We have to find the probability of observing at least one car during any 5 minute time interval.

Probability is the likeliness of happening an event among all the events possible. It is calculated as number/ total number. Its value lies between 0 and 1.

Probability during 20 minutes interval=609/625

Probability during 1 minute interval=609/625*20

=609/12500

Probability during 5 minute interval=(609/12500)*5

=609/2500

Hence the probability of observing at least one car during any 5 minute time interval is 609/2500.

Learn more about probability at brainly.com/question/24756209

#SPJ4

8 0
2 years ago
Two automobiles start together from the same place and travel along the same route. The first averages 40 miles
natita [175]

Answer:

A. (55 x 5) - (40 x 5)

Step-by-step explanation:

You are solving how much miles (further along) would the second car be after 5 hours.

The first car averages 40 miles per hour. 5 hours later, it will have averaged about 200 miles in 5 hours (40 x 5 = 200).

The second car averages 55 miles per hour. 5 hours later, it will have averaged about 275 miles in 5 hours (55 x 5 = 275)

Subtract: 275 - 200 = 75

The second car would have averaged 75 more miles than the first car.

~

4 0
3 years ago
Read 2 more answers
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