Ok so 40y2/50y3.... you are going to cancel out the common factor (10)
4y2/5y3..
now apply the exponent rule, which is : xa /xb = 1/ xb-a
so...y2/y3 = 1/ y3 - 2 = 1/y
ANSWER : 4/5y
Answer:
At a combined speed of 6 in/min, it takes us 24 mins to clean the wall
Step-by-step explanation:
Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us
Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.
Let's list the parameters we have:
Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min
Speed of cleaning wall = Height of wall ÷ Time to clean wall
Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall
since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min
1 ft = 12 in
Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6
Time (t) = 24 mins
Since the carton can hold 1000 units of the cubes.
Each unit of cube = 1inch * 1inch *1inch = 1inch³
Total volume = 1000 * 1inch³ = 1000 inch³
To get the dimension: The carton would take the shape of a cube.
Let each side be x.
x*x*x = 1000
x³ = 1000 Take the cube root of both sides.
∛x³ = ∛1000
x = 10
The dimension of the carton is 10 inches by 10 inches by 10 inches
It couldn’t be anything else but C line reflection i’m assuming
Treat??
hope this helps lol
