I’m pretty sure ‘side QR’ should be 50cm since ‘side AB’ measures 50 and they are equal sides. hope that helped, if not let me know :)
Answer:
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Answer:
The length and width are 11ft and 5ft respectively
Step-by-step explanation:
let the
length = L
Width = W
Area = LW = 55
The length is nine feet less than four times the width
L = 4W - 9
W (4W - 9) = 55
4W^2 - 9W -55 = 0
4W^2 - 20W + 11W - 55 = 0
4W(W - 5) + 11(W - 5) = 0
(W - 5)(4W + 11) = 0
W - 5 = 0 , 4W + 11=0
W = 5 or - 11/4
since the width cannot be negative, W = 5
LW = 55
L = 55/5
L = 11
The length and width are 11ft and 5ft respectively.
Answer:
1) m∠U = 90°
2) m∠C = 80°
Step-by-step explanation:
1) The given figure is a quadrilateral
The sum of the interior angles of quadrilateral = 360°
∴ The sum of the interior angles of the given figure = 360°
Therefore, we have;
80° + 24·x + 4 + 6 + 21·x + 90° = 360°
80° + 45·x + 10 + 90° = 360°
x = (360°- (80° + 10° + 90°))/45 = 4
x = 4
m∠U = 6 + 21·x = 6 + 21 × 4 = 90
m∠U = 90°
2) The sum of the interior angles of the given quadrilateral = 360°
∴ 21·x + 6 + 20·x + 24·x + 4 + 21·x + 6 = 360°
86·x + 16 = 360°
x = (360° - 16°)/86 = 4
x = 4
m∠C = 20·x = 20 × 4 = 80
m∠C = 80°
3) In the figure, some angles are left out, therefore, more information on the remaining angles required
