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3 years ago

The Nile River is 6,690 kilometers long. This is 1,160 kilometers longer than the Yangtze River. How long is the Yangzte River?

Mathematics

1 answer:

natta225 [31]3 years ago

4 0

It is 7,850 kilometers long.

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What is the contrapositive of the conditional statement? If two variables are directly proportional, then their graph is a linea

Triss [41]

Answer:

D. "If the graph of two variables is not a linear function, then the two variables are not directly proportional"

Step-by-step explanation:

The contrapositive of a statement is basically you changing the conditional part of the statement with its result and then finding the negative of both. This is called Contraposition.

So, for the statement given:

"If two variables are directly proportional, then their graph is a linear function."

The contrapositive will be:

"If the graph of two variables is not a linear function, then the two variables are not directly proportional"

7 0

3 years ago

If two cards are drawn without replacement from an ordinary deck, find the probability of and a being drawn.

Ivan

Answer:

4/52

Step-by-step explanation:

4 0

3 years ago

In the diagram shown, line m is parallel to line n. Robert says that ∠2 and ∠7 are supplementary angles. Is he correct? Why or w

bekas [8.4K]

Robert is not correct because in order for it to be supplementary the angles have to be consecutive interior

6 0

3 years ago

write an equation you could use to find the length of the missing side of each triangle. Then find the missing length. Round to

blondinia [14]

Where is the information on the triangles?

8 0

3 years ago

Simplify the expression csc(-x)/1+tan^2x)

Charra [1.4K]

Assuming ya meant $\frac{csc(-x)}{1+tan^2(x)}$

to slimplify, we use a variation of the pythagorean identity and a decomposition into the sin and cos

for the pythaogreaon identity
$cos^2(x)+sin^2(x)=1$
divide both sides by $cos^2(x)$
$1+tan^2(x)=sec^2(x)$ since $\frac{sin(x)}{cos(x)}=tan(x)$
subsitute
$\frac{csc(x)}{sec^2(x)}$

recall that $csc(x)=\frac{1}{cos(x)}$
also that cos(x) is an even function and thus cos(-x)=cos(x)
therfore $csc(-x)=\frac{1}{cos(-x)}=\frac{1}{cos(x)}=csc(x)$
so we get

$\frac{csc(x)}{sec^2(x)}$
decompose them into $\frac{1}{cos(x)}$ and $\frac{1}{sin^2(x)}$ to get $\frac{\frac{1}{cos(x)}}{\frac{1}{sin^2(x)}}$
multiply by $\frac{sin^2(x)}{sin^2(x)}$ to get
$\frac{sin^2(x)}{cos(x)}$
we can furthur simlify to get
$(\frac{sin(x)}{cos(x)})(sin(x))=tan(x)sin(x)$
the expression simplifies to tan(x)sin(x)

5 0

3 years ago

Read 2 more answers