So in order to find line AC you must find line AD and DC then plus them together.
to find AD use Pythagoras theorem
a^2 = c^2 - b^2
AD^2 = 7.5^2 - 6.5^2
AD^2 = 56.25 - 42.25
AD^2 = 14
square root both sides to get rid of the ^2
AD ≈ 3.7 or 3.74
Do the same for DC
DC^2 = 10^2 - 6.5^2
DC^2 = 100 - 42.25
DC^2 = 57.75
DC ≈ 7.6
now plus AD and DC which should give u 11.3
The answer is 0
I took the test and got it right i hope this helps someone
Answer:
![p=10\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D10%5Csqrt%5B3%5D%7B54%7Dx%5E2)
Step-by-step explanation:
We are given parallelogram
Since, two opposite sides of any parallelogram are always equal
Let's assume first side =a
second side =b
so, we get
![a=2\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=a%3D2%5Csqrt%5B3%5D%7B54%7Dx%5E2)
![b=3\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=b%3D3%5Csqrt%5B3%5D%7B54%7Dx%5E2)
now, we can find perimeter
perimeter=2a+2b
so, we get
![p=2(2\sqrt[3]{54}x^2)+2(3\sqrt[3]{54}x^2)](https://tex.z-dn.net/?f=p%3D2%282%5Csqrt%5B3%5D%7B54%7Dx%5E2%29%2B2%283%5Csqrt%5B3%5D%7B54%7Dx%5E2%29)
we can simplify it
![p=4\sqrt[3]{54}x^2+6\sqrt[3]{54}x^2](https://tex.z-dn.net/?f=p%3D4%5Csqrt%5B3%5D%7B54%7Dx%5E2%2B6%5Csqrt%5B3%5D%7B54%7Dx%5E2)
................Answer