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vitfil [10]
3 years ago
6

3) Both Sabrina and Rex are saving money for a big purchase. Sabrina currently

Mathematics
1 answer:
finlep [7]3 years ago
6 0

Answer:

Approx 6 weeks

Step-by-step explanation:

Represent Sabrina's savings by S(w) = $112 + ($10/wk)w, and

Rex's by R(w) = $84 + ($15/wk)w.

Equate these to determine the number of weeks it will take for their respective savings to become equal:

$112 + ($10/wk)w = $84 + ($15/wk)w

first, combine the constant dollar amounts:

$112 - $84 + ($10/wk)w = ($5/wk)w

next, subtract  ($5/wk)w  from both sides, obtaining:

$28 = ($5/wk)w

Finally, divide both sides by  ($5/wk)w, obtaining:

w = 5.6 weeks

Thus, the answer here is that Rex will have more money saved than Sabrina after 5.6 weeks; we could round that off to 6 weeks.

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15/32 × 8/15??<br>please answer quick​
Yuliya22 [10]

Answer:

1/4

Step-by-step explanation:

3 0
2 years ago
A standard-size bass drum has a diameter of 22 inches and is 18 inches deep. Find the volume of this drum
Lena [83]

Answer:

V=1,244.071

Step-by-step explanation:

I put the answer in decimal form and rounded up from .0706, but pi form in included in the pic. I hope this helped! Please leave Brainliest if it did and is right.

4 0
3 years ago
you must attend a minimum of 85% of the practices in order to play in the playoffs you have made 37 of the 42 practices will you
Deffense [45]
Yes, you'd be able to play.
37/42 = .88 = 88%
So you've attended more than 85% of the practices.
3 0
2 years ago
I NEED THIS ASAP, PLEASE HELP!!!
WINSTONCH [101]

Answer: 22.5 ; 5 ; 14

Step-by-step explanation:

Given the dataset:

{20,22,23,24,26,26,28,29,30}

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 9

Q1 = 1/4 (9 + 1)th term

Q1 = 1/4(10) = 2.5

We average the 2nd and 3rd term:

(22 + 23) / 2

45 / 2 = 22.5

B) The interquartile range(IQR) of the dataset :

{62,63,64,65,67,68,68,68,69,74}

IQR = Q3 - Q1

The lower quartile (Q1) = 1/4(n + 1)th term

Where n = number of observations, n = 10

Q1 = 1/4 (10 + 1)th term

Q1 = 1/4(11) = 2.75 term

We take the average of the 2nd and 3rd term:

(63 + 64) / 2

45 / 2 = 63.5

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 10

Q3 = 3/4 (10 + 1)th term

Q3 = 3/4(11) = 8.25 term

We take the average of the 8th and 9th term:

(68 + 69) / 2

137 / 2 = 68.5

IQR = Q3 - Q1

IQR = 68.5 - 63.5

IQR = 5

C) give the dataset :

{7,8,8,9,10,12,13,15,16}

The upper quartile (Q3) = 3/4(n + 1)th term

Where n = number of observations, n = 9

Q3 = 3/4 (9 + 1)th term

Q3 = 3/4(10) = 7.5 term

We take the average of the 7th and 8th term:

(13 + 15) / 2

28 / 2 = 14

7 0
3 years ago
Of a total of 100 buses operated within a particular town, 48 usually run on time and 36 of these buses are owned by Jerry. Of t
miv72 [106K]
Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.

Below is similar question:

<span>48 out of 100 private buses usually run on time. Out of the buses that are on time, only 36 are owned by Jerry. Out of the remaining 52 buses that usually run late, only 7 are owned by Jerry. What is the probability that a bus is owned by Jerry, given that it runs on time?
 A. 0.58
B. 0.67
C. 0.75
D. 0.81
</span>
The answer is C as <span>36/48 = .75</span>
4 0
3 years ago
Read 2 more answers
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