The radius would be 10 and the arc would be 5.
I hope this helps.
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Hello :
answer ; B
because : x=8.....y=-12(8)-3 =-99
-24a²- 6a +9 = - 3(8a² +6a - 9)
8a² +6a - 9 =0
x=(-b +/-√(b² - 4ac))/2a
x = (-6 +/-√(36+4*8*9) /(2*8) = (-6 +/-√(324) /16 = (-6 +/-18)/16
x1 = (-6 +18)/16 = 0.75
x2 = (-6 -18)/16 = - 1.5
-24a²- 6a +9 = - 3(8a² +6a - 9) = -3(a - 0.75)(a + 1.5)
Answer:
Therefore the car takes 2 s to reach a minimum height from the ground before rising again.
Step-by-step explanation:
Given that a roller coaster ride reach a height of 80 feet.
The height above the ground of the roller coaster is modeled by the function
h(t)=10t²-40t+80
where t is measured in second.
h(t)=10t²-40t+80
Differentiating with respect to t
h'(t)= 10(2t)-40
⇒h'(t)=20t-40
To find the minimum height we set h'(t)=0
∴20t-40=0
⇒20t =40
⇒t=2
The height of the roller coaster minimum when t=2 s.
The minimum height of of the roller coaster is
h(2)= 10(2)²-40.2+80
=40-80+80
=40 feet.
Therefore the car takes 2 s to reach a minimum height from the ground before rising again.
