The area of Tinyville if the population of Tinyville is 405 Tinys while the population density of the Tinyville is 16.2 is 25 Acres.
<h3>What is Ratio?</h3>
A ratio shows us the number of times a number contains another number.
As it is given that the population density of Tinyville is 16.2 Tinys per acre, while the population of Tinyville is 405 Tinys. Therefore, the area of the Tinyville is the ratio of the population of Tinyville to the population density of the Tinyville.
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
Hence, the area of Tinyville if the population of Tinyville is 405 Tinys while the population density of the Tinyville is 16.2 is 25 Acres.
Learn more about Ratio:
brainly.com/question/1504221
Answer:
4'4
Step-by-step explanation:
Answer:
Step-by-step explanation:
you mean u=ln x,v=ln y
ln(x^3y^2)=lnx^3+ln y^2
=3 ln x+2 ln y
=3u+2v
Answer:
a=170
Step-by-step explanation:
(a+10)=180[because being a straight line]
or, a+10=180
or,a=180-10
a=170
Therefore,a=170
Arc length is figured by the following formula theta/360 x 2pi(r) input the knowns 30/360x2pi(20)=11.52 miles