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Luba_88 [7]
2 years ago
6

What is the value of x?

Mathematics
1 answer:
Norma-Jean [14]2 years ago
3 0
You can Calculate the mass of magnesium sulphate obtained from 5g of magnesium.
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Use quadratic formula to solve 1-6x^2-x​
eduard

Answer:

(3x-1)(2x+1)

Step-by-step explanation:

1-6x^2-x=0

-6x^2-x+1=0

6x^2+x-1=0

6x^2+(3-2)x-1=0

6x^2+3x-2x-1=0

3x(2x+1)-1(2x+1)=0

(3x-1)(2x+1)=0

So the factor is (3x-1)(2x+1)

6 0
3 years ago
Whats -5n+12n+9+(-3) some one help me with this one
nikdorinn [45]

-5n+12n+9+(-3)

-5n+12n+9-3

7n+9-3

=7n+6

Hope this helps!

Thank you for posting your question at here on Brainly.

-Charlie

8 0
3 years ago
Please help me with vivid explanation​
Ivanshal [37]

Answer:

864 m²

Step-by-step explanation:

  • First calculate the total area of the rectangular field

The area of a rectangle is given by the product of the length and the width

let A be the total area

A = 100*120

A = 12000 m²

Calculate the area of the small rectangles

  • Let A' be the total area of the four small rectangles and A" the area of one small rectangle
  • A' = 4 A"
  • A' = 4 [(\frac{120-4}{2})*(\frac{100-4}{2})]
  • A' = 4*58*48
  • A' = 11136 m²

  • Substract the A' from A to get the area of the road

Let A"' be the area of the road

A"' =A-A'

A"' = 12000-11136

A"' = 864 m²

3 0
3 years ago
SC.6.E.6.14.
tester [92]
It has to be A I’m sorry if I’m wrong
4 0
2 years ago
Read 2 more answers
Suppose the average price of gasoline for a city in the United States follows a continuous uniform distribution with a lower bou
Novay_Z [31]

Answer:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

And for this case we can write the probability like this:

P(X

And then the final answer for this case would be \frac{2}{3}=0.667

Step-by-step explanation:

For this case we define our random variable X "price of gasoline for a city in the USA" and we know the distribution is given by:

X \sim Unif (a=3.5, b=3.8)

And for this case the density function is given by:

f(x) = \frac{x}{b-a}= \frac{x}{3.8-3.5}=, 3.5 \leq X \leq 3.8

And we want to calculate the following probability:

P(X

And we can use the cumulative distribution function given by:

F(x) = \frac{x-a}{b-a} , a \leq X \leq b

And for this case we can write the probability like this:

P(X

And then the final answer for this case would be \frac{2}{3}=0.667

5 0
3 years ago
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