Karin observed that the water level in the part of the river she observed fell 1.68 millimeters per year for 1.5 years. Use the
distributive property to calculate the exact variation in water level for the time period
1 answer:
<em><u>Answer</u></em>
In order to use the distributive property I first get the amount of the water fell in ;
<u>One </u><u>year</u>
1.68mm
<u>A </u><u>half</u><u> </u><u>a </u><u>year</u>
½× 1.68mm
= 0.84mm
<u>One </u><u>and </u><u>a </u><u>half </u><u>years (</u><u>Using </u><u>the</u><u> </u><u>distributive</u><u> </u><u>property</u><u>)</u>
1.68mm + 0.84mm
<u>1</u><u>6</u><u>8</u><u>m</u><u>m</u> + <u>8</u><u>4</u><u>m</u><u>m</u>
100. 100
(168÷100) + (84÷100)
(168+84) ÷ 100
252 ÷ 100
<u>2</u><u>5</u><u>2</u>
100
= 2.52mm
Therefore the variation in the water level in the time period was 2.25mm
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