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Vlada [557]
3 years ago
15

Solve log2(log5x)=3

Mathematics
2 answers:
belka [17]3 years ago
6 0

Answer:

I took the test and got 100%

1. B

2. D

3. A

4. Answer will vary

5. f will equal g when the value of X is less than 0

g is greater than f if the value of X is less than 0

f is greater than g if the value of X is greater than 0

6. C

7. C

8. B

9. B

10. C

Feel free to mark as brainliest and your welcome in advance :)

julsineya [31]3 years ago
5 0

Given expression: \log _2\left(\log _5\left(x\right)\right)=3.

\mathrm{Apply\:log\:rule}:\quad \:a=\log _b\left(b^a\right)

3=\log _2\left(2^3\right)=\log _2\left(8\right)

\log _2\left(\log _5\left(x\right)\right)=\log _2\left(8\right)

\mathrm{For\:}\log _2\left(\log _5\left(x\right)\right)=\log _2\left(8\right)\mathrm{,\:\quad solve\:}\log _5\left(x\right)=8

\log _5\left(x\right)=8

Converting log to exponential form.

log_{b} x = a \ \ \ \ =>x = b^a

x = 5^8

x=390625.

<h3>Therefore, correct option is C: x=390,625.</h3>
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0.9 of Karen's Science score is equal to 0.75 of her Math score and 0.8 of her Chemistry score. Given that Karen scored 96 marks
DochEvi [55]

You have to formulate equations for this problem.

Let S = Science score

      M = Math score

       C = Chemistry score

To illustrate the given:

0.9S = 0.75M

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You are given that Karen’s Math score is 96 marks. You have to substitute the Math score to the first equation.

0.9S = 0.75(96)

0.9S = 72

S = 80

Therefore, Karen’s Science score is 80. Now, you have to substitute the Science score to the second equation.

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4 years ago
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Gnesinka [82]

Answer:

540

Step-by-step explanation:

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4 0
4 years ago
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mixer [17]
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Find the standard form of the equation of the circle with endpoints of a diameter at the points (9,2) and (-7.4).
kicyunya [14]

Answer:

(x-1)²+(y-3)²=65

Step-by-step explanation:

the common view of the equation of a circle is:

a) (x-a)²+(y-b)²=r², where (a;b) - the centre of the required circle, r - the radius of the required circle;

b) using the coordinates of the endpoint of the given diameter it is possible to calculate the coordinates of the centre of the required circle and its radius²:

the coordinate x of the required circle is: (9-7)/2=1;

the coordinate y of the required circle is: (2+4)/2=3.

the radius² of the required circle is:

r²=0.25*[(9- -7)²+(2-4)²]=0.25*260=65.

c) after the substitution the values of 'a'; 'b' and 'r²' into the common equation of the circle:

(x-1)²+(y-3)²=65.

PS. additional: the given points (9;2) and (-7;4) belong to the final equation, if to substitute their coordinates into it.

The suggested way of solution is not the only one.

5 0
3 years ago
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