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rosijanka [135]
4 years ago
14

at the beginning of the day the stock market goes up 301/2 points. at the end of the day the stock market goes down 120 1/4 poin

ts. what is the total change in the stock market from the beginning of the day to the end of the day?
Mathematics
2 answers:
Crazy boy [7]4 years ago
8 0

let's change the mixed fractions first to improper fractions and then get their sum.

we don't know the beginning point of the market, however from that point on, it spikes up by 30½and then goes down by 120¼, we're being asked on the total change or namely the displacement, and that'd be the sum of the spike line going up and the dive line going down.

\bf \stackrel{mixed}{30\frac{1}{2}}\implies \cfrac{30\cdot 2+1}{2}\implies \stackrel{improper}{\cfrac{61}{2}}~\hfill \stackrel{mixed}{120\frac{1}{4}}\implies \cfrac{120\cdot 4+1}{4}\implies \stackrel{improper}{\cfrac{481}{4}} \\\\[-0.35em] ~\dotfill\\\\ \cfrac{481}{4}+\cfrac{61}{2}\implies \stackrel{\textit{using an LCD of 4}}{\cfrac{(1)481+(2)61}{4}}\implies \cfrac{481+122}{4}\implies \cfrac{603}{4}\implies 150\frac{3}{4}

Feliz [49]4 years ago
7 0

Answer:

just saying

Step-by-step explanation:

subtract them lol use a mixed number calculator online

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user100 [1]

Answer:

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Step-by-step explanation:

I get it you have to put the number into your calculator then turn it into a fraction

hop this helps

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8 0
3 years ago
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pav-90 [236]

Answer:

Parallelogram Height = 6 cm * sine (60)

Height = 6 * 0.86603

Height = 5.19618

Parallelogram Area = Height * Side TH

Parallelogram Area = 5.19618 * 8

Parallelogram Area = 41.56944 square cm

You might find this page helpful: https://www.1728.org/quadpar.htm


Step-by-step explanation:


5 0
4 years ago
In a right triangle ΔABC, the length of leg AC = 5 ft and the hypotenuse AB = 13 ft. Find: Chapter Reference b The length of the
Butoxors [25]

Answer:

The length of the angle bisector of angle ∠A is 6.01.

Step-by-step explanation:

It is given that length of leg AC = 5 ft and the hypotenuse AB = 13 ft.

Using pythagoras theorem

(AB)^2=(BC)^2+(AC)^2

(13)^2=(BC)^2+(5)^2

169=(BC)^2+25

BC=12

\sin A=\frac{\text{perpendicular}}{\text{hypotenuse}}

\sin A=\frac{BC}{AB}

A=\sin ^{-1}\frac{12}{13}

A=67.38

Bisector divides the angle in two equal parts, therefore,

A'=\frac{67.38}{2} =33.69

In triangle ACD.

\cos A'=\frac{\text{Base}}{\text{Hypotenuse}}

\cos A'=\frac{AC}{AD}

\cos (33.69^{\circ})=\frac{5}{AD}

0.832=\frac{5}{AD}

AD=\frac{5}{0.832} =6.009\approx 6.01

Therefore the length of the angle bisector of angle ∠A is 6.01.

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3 years ago
Simplify the following cos(-x)tanx
RSB [31]
\bf \textit{symmetry identites}\\\\
cos(-\theta)=cos(\theta)\\\\
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3 years ago
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MrRissso [65]

Answer:

the answer is A=8.96 X 10 with a power of 7

5 0
3 years ago
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