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ivanzaharov [21]
3 years ago
8

Starting at an initial position of 100 meters, a person jogs at 5 meters per second for 1 minute forward and then walks backward

s at 2 meters per second for 2 minutes. What position does the person end at?
Mathematics
1 answer:
il63 [147K]3 years ago
6 0

Answer:

100 + (5 * 60) = 400

400 - (2*120) = 160

end position = 160

Step-by-step explanation:

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 ×2  ×2  ×2

a_{n} = a_{1} * r^{n - 1}
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           First Term: 8
      Second Term: 16
          Third Term: 32
        Fourth Term: 64
           Fifth Term: 128
          Sixth Term: 256
     Seventh Term: 512
       Eighth Term: 1024
         Ninth Term: 2048
        Tenth Term: 4096
   Eleventh Term: 8192
     Twelfth Term: 16384
Thirteenth Term: 32768

The\ expression\ that\ would\ give\ the\ thirteenth\ term\ of\ the\ problem\ would\ be\ the\ equation\ of\ the\ geometric\ sequence,\ which\ is\ equal\ to\ a_{n} = a_{1} * r^{n - 1}.

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