Given,
We can use L'Hopital's Rule to get,
![\lim_{x}^{a}\dfrac{2}{3-\sqrt[3]{x}}](https://tex.z-dn.net/?f=%5Clim_%7Bx%7D%5E%7Ba%7D%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Bx%7D%7D)
Now plug in a,
![\boxed{\dfrac{2}{3-\sqrt[3]{a}}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cdfrac%7B2%7D%7B3-%5Csqrt%5B3%5D%7Ba%7D%7D%7D)
Hope this helps.
r3t40
Answer:
x-41
Step-by-step explanation:
use the foil method
Answer:
there is a cluster from 1-4
there is a gap from 5-7
The spread is from 1-8
Step-by-step explanation:
These are all true if you look... there is a bunch from 1-4, there is none from 5-7, and all of them are within 1-8, but the highest amount isn't at 3.
Answer:
answer is 57.
Step-by-step explanation:
Given
m<6= x - 8
m<7 = 2x - 7
We know
<6 + <7 = 180° [ being linear pair ]
x - 8 + 2x - 7 = 180°
3x - 15 = 180°
3x = 180° + 15°
3x = 195°
x = 195° / 3
x = 65°
Now
m<6= x - 8 = 65° - 8° = 57°
hope it helps :)
