Answer:
The number of seniors who scored above 96% is 1.
Step-by-step explanation:
Consider the provided information.
Two percent of all seniors in a class of 50 have scored above 96% on an ext exam.
Now we need to find the number of seniors who scored above 96%
For this we need to find the two percent of 50.
2% of 50 can be calculated as:
Hence, the number of seniors who scored above 96% is 1.
Answer:
1)60
2)7
Step-by-step explanation:
1)The square root of 3600 is 60. It is the positive solution of the equation x2 = 3600. The number 3600 is a perfect square.
2)The cube root of 343 is the number which when multiplied by itself three times gives the product as 343. Since 343 can be expressed as 7 × 7 × 7. Therefore, the cube root of 343 = ∛(7 × 7 × 7) = 7.
Answer:
51in
Step-by-step explanation:
you first have to find the area of the square by multiplying 6 and 7 which is 42. Then you have to find area of the triangle and the formula to do that is (length×width)÷2 . to find the length you have to subtract 7 from 13 which is 6 and the length you have to do 6-3 which is 3 then (6×3)÷2=9 and then you add the area of the square and the area of the triangle and get 42+9=51
Another ratio of 13:27 is to write it as a fraction. This is to mean;
The work done in pushing the box is 64000 lb-ft²/s²
<h3>How to calculate the work done by the person?</h3>
Since person pushing a 40 pound box up an incline that is 30 degrees above the horizontal and 100 feet long, the work done, W is
W = mgh where
- m = mass of box = 40 lb,
- g = acceleration due to gravity = 32 ft/s² and
- h = height of incline = LsinФ where
- L = length of incline = 100 ft and
- Ф = angle of incline = 30°
So, W = mgh
W = mgLsinФ
So, substituting the values of the variables into the equation, we have
W = mgLsinФ
W = 40 lb × 32 ft/s² × 100 ftsin30°
W = 1280 lb-ft/s² × 100 ft × 0.5
W = 1280 lb-ft/s² × 50 ft
W = 64000 lb-ft²/s²
So, the work done in pushing the box is 64000 lb-ft²/s²
Learn more about work done here:
brainly.com/question/25970931
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