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lozanna [386]
3 years ago
14

Si en una empresa hay 120 trabajadores 3/8 son españoles y el resto europeos. Cuántos europeos hay?

Mathematics
1 answer:
Kobotan [32]3 years ago
8 0

Answer:

75 Europeos

Step-by-step explanation:

3/8 X 120= 360/8 = 45

120-45= 75

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Find the remaining trigonometric ratios of θ if csc(θ) = -6 and cos(θ) is positive
VikaD [51]
Now, the cosecant of θ is -6, or namely -6/1.

however, the cosecant is really the hypotenuse/opposite, but the hypotenuse is never negative, since is just a distance unit from the center of the circle, so in the fraction -6/1, the negative must be the 1, or 6/-1 then.

we know the cosine is positive, and we know the opposite side is -1, or negative, the only happens in the IV quadrant, so θ is in the IV quadrant, now

\bf csc(\theta)=-6\implies csc(\theta)=\cfrac{\stackrel{hypotenuse}{6}}{\stackrel{opposite}{-1}}\impliedby \textit{let's find the \underline{adjacent side}}
\\\\\\
\textit{using the pythagorean theorem}\\\\
c^2=a^2+b^2\implies \pm\sqrt{c^2-b^2}=a
\qquad 
\begin{cases}
c=hypotenuse\\
a=adjacent\\
b=opposite\\
\end{cases}
\\\\\\
\pm\sqrt{6^2-(-1)^2}=a\implies \pm\sqrt{35}=a\implies \stackrel{IV~quadrant}{+\sqrt{35}=a}

recall that 

\bf sin(\theta)=\cfrac{opposite}{hypotenuse}
\qquad\qquad 
cos(\theta)=\cfrac{adjacent}{hypotenuse}
\\\\\\
% tangent
tan(\theta)=\cfrac{opposite}{adjacent}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{adjacent}{opposite}
\\\\\\
% cosecant
csc(\theta)=\cfrac{hypotenuse}{opposite}
\qquad \qquad 
% secant
sec(\theta)=\cfrac{hypotenuse}{adjacent}

therefore, let's just plug that on the remaining ones,

\bf sin(\theta)=\cfrac{-1}{6}
\qquad\qquad 
cos(\theta)=\cfrac{\sqrt{35}}{6}
\\\\\\
% tangent
tan(\theta)=\cfrac{-1}{\sqrt{35}}
\qquad \qquad 
% cotangent
cot(\theta)=\cfrac{\sqrt{35}}{1}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}

now, let's rationalize the denominator on tangent and secant,

\bf tan(\theta)=\cfrac{-1}{\sqrt{35}}\implies \cfrac{-1}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{-\sqrt{35}}{(\sqrt{35})^2}\implies -\cfrac{\sqrt{35}}{35}
\\\\\\
sec(\theta)=\cfrac{6}{\sqrt{35}}\implies \cfrac{6}{\sqrt{35}}\cdot \cfrac{\sqrt{35}}{\sqrt{35}}\implies \cfrac{6\sqrt{35}}{(\sqrt{35})^2}\implies \cfrac{6\sqrt{35}}{35}
3 0
3 years ago
Solve for W
umka2103 [35]

In this equation w = -1.1

In order to find this, get all w values to the right side and all numbers to the left side.

-2.27 + 9.1w + 1.3w = -3.4w - 17.45 ----> combine like terms

-2.27 + 10.4w = -3.4w - 17.45 ----> add 3.4w to both sides

-2.27 + 13.8w = -17.45 ----> add 2.27 to both sides

13.8w = -15.18 -----> divide both sides by 13.8

w = -1.1

4 0
3 years ago
Read 2 more answers
What is the variable in the expression below?<br><br><br> 9.X
Ludmilka [50]

Answer:

The variable in that expression is x

5 0
3 years ago
Read 2 more answers
what is the slope of the line that passes through the points (7,-6) and (4,-6)? write your answer in simplest form
Andrews [41]

Answer:

<u>m = 0</u>, y = -6

Step-by-step explanation:

using point slope form :

y - y_{1} = m(x - x_{1})

y-y1=m(x-x1) ; initial point (x1,y1) = (4,-6), final point (x,y) = (7,-6).

one substituted, it should look like this:

-6--6 = m(7-4),

-6+6= m(7-4)

0 = m(7-4)

0 = 3m

0/3 = 3/3m

0 = m

m = 0/3 = 0

4 0
3 years ago
A school is preparing a trip for 400 students. The company who is providing the transportation has 10 buses of 50 seats each and
Naya [18.7K]
<h2>The number of small buses used = 5</h2><h2>The number of big buses used  = 4</h2>

Step-by-step explanation:

Let us assume the total number of small buses needed = x

The capacity of 1 small bus  = 40

So, the capacity of x buses  = 40(x)  = 40 x

Let us assume the total number of big buses needed = y

The capacity of 1 big bus  = 50

So, the capacity of y buses  = 50(y)  = 50 y

Also, the total students travelling = 400

So, the number of students traveling by (Small bus + Big bus)  = 400

⇒ 40 x + 50 y = 400 ..... (1)

Also, the total number of drivers available  = 9

⇒ x +  y = 9  ..... (2)

Also, x  ≤ 8,   y ≤ 10

Now, solving both equations, we get:

40 x + 50 y = 400 ..... (1)

x +  y = 9  ⇒ y = (9-x) put in (1)

40 x + 50 y = 400  ⇒  40 x  + 50 (9-x)  = 400

or, 40 x  + 450 - 50 x  = 400

or, - 10 x  =- 50

or, x  = 5 ⇒ y = (9-x)  = 9- 5 = 4

Hence the number of small buses used = 5

The number of big buses used  = 4

8 0
4 years ago
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