Answer:
a. The time to strike the ground is 5 seconds
b. The time for the ball to be over than 96 ft is 1 second
Step-by-step explanation:
a. When the ball thrown vertically up ward to reach its maximum height at velocity = 0 then complete its motion vertically down ward to strike the ground its displacement = zero
∴ s(t) = 0 ⇒ 
∴
5 - t = 0⇒ ∴ t = 5 seconds
b. To tind the time that the ball will be over 96 ft over the ground substitute in 




t = 3 sec. and t = 2 sec.
The ball will be at height 96 ft at time 2 sec. and 3 sec.
So the ball will be at height over than 96 = 3 - 2 = 1 sec.
Answer:
0
Step-by-step explanation:
4[24-3(7x+6)]-6(4-14x)
4(24-21x-18)-24+84x
96-84x-72-24+84x
96-72-24-84x+84x
0 + 0
0
8x^3y^4(3 sqrt xy) LETTER A :)
Mean is the average. You would add up all the numbers and divide by how many numbers you have. 433/10=43.3
The answer is 1014. Look at my work...