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2 years ago

How many terms are there in the following expression? x - 5 + 16x + 4 - 2x - 3

Mathematics

1 answer:

k0ka [10]2 years ago

3 0

Answer:

Two terms

Step-by-step explanation:

First, we have to simplify reducing the number of terms, since there are like terms

x-5+16x+4-2x-3

Eventually, you'll get 15x-4, thus there are two terms.

Please correct me if I'm incorrect, and I'll change the answer, but I hope I helped :)

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2 years ago

The formula for calculating the density of an object is D=-, where m is mass and v is volume.

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Answer:

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Step-by-step explanation:

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3 years ago

A quadratic equation of the form 0 = ax2 + bx + c has one real number solution. Which could be the equation?

Fynjy0 [20]

Answer:

The equation showing this situation is $D=b^2-4ac=0$

Step-by-step explanation:

Given : A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

To find : Which could be the equation?

Solution :

A quadratic equation in form $ax^2+bx+c=0$ has a solution $x=\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ called a quadratic formula in which the roots are one real,two real or no real is determine by discriminant factor.

Discriminant is defined as to determine the number of roots in a quadratic equitation has following rules :

1) If $D=b^2-4ac>0$ there are two real roots.

2) If $D=b^2-4ac=0$ there are one real roots.

3) If $D=b^2-4ac$ there are no real roots.

According to question,

A quadratic equation of the form $ax^2 + bx + c=0$ has one real number solution.

So, The equation showing this situation is $D=b^2-4ac=0$

6 0

3 years ago

Ex 3.6<br> 6. find the area enclosed between the curve y= -2x²-5x+3 and the x-axis

Xelga [282]

When y=0,

$-2{ x }^{ 2 }-5x+3=0\\ \\ 2{ x }^{ 2 }+5x-3=0\\ \\ \left( 2x-1 \right) \left( x+3 \right) =0$

$\\ \\ \therefore \quad x=\frac { 1 }{ 2 } \\ \\ \therefore \quad x=-3$

--------------------

$\int _{ -3 }^{ \frac { 1 }{ 2 } }{ -2{ x }^{ 2 } } -5x+3dx$

$\\ \\ ={ \left[ -\frac { { 2x }^{ 2+1 } }{ 2+1 } -\frac { 5{ x }^{ 1+1 } }{ 1+1 } +3x \right] }_{ -3 }^{ \frac { 1 }{ 2 } }$

$\\ \\ ={ \left[ -\frac { 2{ x }^{ 3 } }{ 3 } -\frac { 5{ x }^{ 2 } }{ 2 } +3x \right] }_{ -3 }^{ \frac { 1 }{ 2 } }$

$\\ \\ \\ =\left\{ -\frac { 2 }{ 3 } { \left( \frac { 1 }{ 2 } \right) }^{ 3 }-\frac { 5 }{ 2 } { \left( \frac { 1 }{ 2 } \right) }^{ 2 }+3\left( \frac { 1 }{ 2 } \right) \right\} -\left\{ -\frac { 2 }{ 3 } { \left( -3 \right) }^{ 3 }-\frac { 5 }{ 2 } { \left( -3 \right) }^{ 2 }+3\left( -3 \right) \right\}$

$\\ \\ \\ =-\frac { 2 }{ 3 } \cdot \frac { 1 }{ 8 } -\frac { 5 }{ 2 } \cdot \frac { 1 }{ 4 } +\frac { 3 }{ 2 } -\left\{ -\frac { 2 }{ 3 } \left( -27 \right) -\frac { 5 }{ 2 } \cdot 9-9 \right\}$

$\\ \\ =-\frac { 2 }{ 24 } -\frac { 5 }{ 8 } +\frac { 3 }{ 2 } -\left\{ \frac { 54 }{ 3 } -\frac { 45 }{ 2 } -9 \right\}$

$\\ \\ =-\frac { 2 }{ 24 } -\frac { 15 }{ 24 } +\frac { 36 }{ 24 } -\frac { 54 }{ 3 } +\frac { 45 }{ 2 } +9$

$\\ \\ =\frac { 19 }{ 24 } -\frac { 54 }{ 3 } +\frac { 45 }{ 2 } +\frac { 18 }{ 2 } \\ \\ =\frac { 19 }{ 24 } -\frac { 54 }{ 3 } +\frac { 63 }{ 2 }$

$\\ \\ =\frac { 343 }{ 24 }$

Answer: 343/24 units squared.

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3 years ago

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