Answer:
- perimter of original rectangle = <u>17. 6 mm</u>
- side length of the enlarged rectangle = <u>23. 22 mm</u>
- perimeter of the enlarged rectangle = <u>95. 04 mm</u>
Step-by-step explanation:
<u>PERIMETER</u><u> </u><u>OF</u><u> </u><u>ORIGINAL</u><u> </u><u>RECTANGLE</u>
- Length of original rectangle = 4.5 mm
- Width of original rectangle = 4.3 mm
<em>perimeter = 2 × ( length + width)</em>
= 2 × ( 4.5 + 4.3)
= 2 × 8.8
= 17. 6 mm
<u>SIDE</u><u> </u><u>LENGTH</u><u> </u><u>OF</u><u> </u><u>ENLARGED</u><u> </u><u>RECTANGLE</u>
- Width of original rectangle = 4. 5 mm
- Width of enlarged rectangle = 24.3 mm
Enlargement factor = 24.3 / 4.5
= 5.4
- Length of original rectangle = 4.5 mm
- Enlargement factor = 5.4
Side length of enlarged rectangle
= original length × Enlargement factor
= 4.3 × 5.4
= 23. 22 mm
<u>PERIMTER OF ENLARGED RECTANGLE</u>
= 2 × ( enlarged ength + enlarged breadth)
= 2 × (23. 22 + 24. 3 )
= 95. 04 mm
Answer:

General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
<em />
<em />
<em />
<u>Step 2: Simplify</u>
- Combine like terms (x):

- Combine like terms (y):

Answer:
The percentage of students who scored below 620 is 93.32%.
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

Percentage of students who scored below 620:
This is the pvalue of Z when X = 620. So



has a pvalue of 0.9332
The percentage of students who scored below 620 is 93.32%.
I believe the correct answer from the choices listed above is option A. Approximately, there will be 2.61x10^9 cans that will <span> be recycled in 16 days. We calculate as follows:
113204 cans / min (60 min / 1 hr) (24 hr / 1 day) = 163013760 cans / day
</span>163013760 cans / day (16 days) = <span>2.61x10^9 cans
Hope this answers the question.</span>