Answer:
9
Step-by-step explanation:
(200plus79)x(20plus 1)
i am pretty sure
Answer:
c
Step-by-step explanation:
The limit exists because it's continuous since they equal each other
when x approaches zero.
Substitute both expressions with x=0 and both of them will equal 2, so the limit should be 2.
The answer for that problem is z =12+6
$10 because 2 and 3 add together and subtract 15 equals 10
