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stellarik [79]
3 years ago
10

Celeste wants to have her hair cut and permed and also go to lunch. She knows she will need $68. The perm costs twice as much as

her haircut and she needs $5 for lunch. How much does the perm cost?
Mathematics
1 answer:
fgiga [73]3 years ago
8 0
Total is 68 and the perm is 2 times as much as her haircut and her lunch is $5
so...
2h+h+5= 68 (add like terms)
3h+5 = 68    (subtract 5 from both sides)
      -5   - 5
3h = 63 (divide by 3)
h= 21
so if her haircut is 21 dollars
21*2= $42
her perm cost 42 dollars
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liubo4ka [24]

Answer:

Step-by-step explanation:

6/14 = -9/21 = -12/28 = -15/35 = -18/42 = -21/49 = -24/56 = -27/63 = -30/70 = -33/77 = -36/84 = -39/91 = -42/98 = -45/105 = -48/112

6 0
3 years ago
Please please please help and solve this with steps, much help needed thank you :) 20 points for this!
leonid [27]

Answer:

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

(Please vote me Brainliest if this helped!)

Step-by-step explanation:

\frac{dy}{dx}y=x^3+2x-5x+3

\mathrm{First\:order\:separable\:Ordinary\:Differential\:Equation}

  • \mathrm{A\:first\:order\:separable\:ODE\:has\:the\:form\:of}\:N\left(y\right)\cdot y'=M\left(x\right)

1. \mathrm{Substitute\quad }\frac{dy}{dx}\mathrm{\:with\:}y'\:

y'\:y=x^3+2x-5x+3

2. \mathrm{Rewrite\:in\:the\:form\:of\:a\:first\:order\:separable\:ODE}

yy'\:=x^3-3x+3

  • N\left(y\right)\cdot y'\:=M\left(x\right)
  • N\left(y\right)=y,\:\quad M\left(x\right)=x^3-3x+3

3. \mathrm{Solve\:}\:yy'\:=x^3-3x+3:\quad \frac{y^2}{2}=\frac{x^4}{4}-\frac{3x^2}{2}+3x+c_1

4. \mathrm{Isolate}\:y:\quad y=\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+4c_1}{2}}

5. \mathrm{Simplify}

y=\sqrt{\frac{x^4-6x^2+12x+c_1}{2}},\:y=-\sqrt{\frac{x^4-6x^2+12x+c_1}{2}}

7 0
3 years ago
Read 2 more answers
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soldier1979 [14.2K]

For this case we must resolve the following expression:log_ {0.5} (16)

We have to:

log_ {a} (x) = \frac {log_ {b} (x)} {log_ {b} (a)}

The base change rule can be used if a and b are greater than 1 and are not equal to x.

We substitute the values in the base change formula, using b = 10

\frac {log (16)} {log (0.5)} = - 4

Answer:

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Option A

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Step-by-step explanation:

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azamat

Answer:

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