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iogann1982 [59]
2 years ago
11

Directions:Use the product rule to simplify the following monomials.

Mathematics
1 answer:
abruzzese [7]2 years ago
3 0

7) Answer = -24x^8y^{11}

\left(8x^4y^2\right)\left(-3x^4y^9\right)

=-8x^4y^2\cdot \:3x^4y^9

=-24x^4y^2x^4y^9

=-24x^8y^2y^9

=-24x^8y^{11}

8) Answer = -30y^6

2y\left(-5\right)y^2\cdot \:3y^3

=-30yy^2y^3

=-30y^{1+2+3}

=-30y^6

9) Answer = -6x^4y^5

\left(-2xy\right)\left(xy\right)\left(3x^2y^3\right)

=-2xyxy\cdot \:3x^2y^3

=-6xyxyx^2y^3

=-6x^4yyy^3

=-6x^4y^5

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the sum of three numbers is 2100. the first number x is equal to the sum of the other two (y and z) which are equal to each othe
max2010maxim [7]
We will have a system of equations, and we are going to solve it by using substitution.
Let's make the equations.
x+y+z=2100
z+y=x
Since y and z are equal, I think it is easier for us to have them as one variable for now. Let the value of z and y be a.
These are the equations now.
x+2a=2100
2a=x
Since the second equation is giving the value of x, let it replace the value of x also in the first equation.
2a+2a=2100
4a=2100
2100÷4= 525
so, x and y equal 525. Let's put this in our original equation.
x+525+525=2100
x+ 1,050= 2,100
x= 1,050
So, x=1,050, y= 525 =z.

7 0
3 years ago
Need an explanation
aleksandrvk [35]

Answer: Choice B

(6\sqrt{5}+5)i

==========================================================

Work Shown:

\sqrt{-5}+\sqrt{-25}+\sqrt{-125}\\\\\sqrt{-1*5}+\sqrt{-1*25}+\sqrt{-1*25*5}\\\\\sqrt{-1}*\sqrt{5}+\sqrt{-1}*\sqrt{25}+\sqrt{-1}*\sqrt{25}*\sqrt{5}\\\\i*\sqrt{5}+i*5+i*5*\sqrt{5}\\\\i*\sqrt{5}+5i+5i*\sqrt{5}\\\\(i\sqrt{5}+5i*\sqrt{5})+5i\\\\(\sqrt{5}+5\sqrt{5})i+5i\\\\(6\sqrt{5})i+5i\\\\(6\sqrt{5}+5)i\\\\

This points us to answer choice B

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