It would be 2 1/4 because .25 in fraction form is 1/4 because it is a quarter and then 2
Answer:
743.25m^2
Step-by-step explanation:
Area of triangle = 1/2bh
= 1/2 x 30 x 26
= 390
Area of semi circle = 1/2 πr^2
= 1/ 2 x 3.14 x 15 x15
=353.25m^2
= 390 + 353.25
= 743.25m^2
Answer:
Well, the first thing you must do is find the slope
(0,2) (1,-3) I am going to make x1= 0, y1=2, x2=1 and y2= -3
Now, I am going to use the formula for the slope, which is
y2-y1/(x2-x1)
[-3-2]/(1-0)= -5/1 or just -1
Next, I am going to use the point slope form, which is
y-y1=m(x-x1). m=5, x1=0, y1=2
y-2= -5(x-0)
y-2=-5x
+2 +2
y= -5x+2 This is the slope intercept form.
we are done. I am glad to see that you are doing math on a Saturday night.. Good luck... Please rate my answer:)
Answer:
Hence, the probability of exactly 3 successes in 6 trials of a binomial experiment round to the nearest tenth of a percent is:
31.2%
Step-by-step explanation:
The probability of getting exactly k successes in n trials is given by the probability mass function:
![{\displaystyle P(k;n,p)=P(X=k)={\binom {n}{k}}p^{k}(1-p)^{n-k}}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20P%28k%3Bn%2Cp%29%3DP%28X%3Dk%29%3D%7B%5Cbinom%20%7Bn%7D%7Bk%7D%7Dp%5E%7Bk%7D%281-p%29%5E%7Bn-k%7D%7D)
Where p denotes the probability of success.
We are given that the probability of success if 50%.
i.e. ![p=\dfrac{1}{2}](https://tex.z-dn.net/?f=p%3D%5Cdfrac%7B1%7D%7B2%7D)
also form the question we have:
k=3 and n=6.
Hence the probability of exactly 3 successes in 6 trials is:
![{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{3}(1-\dfrac{1}{2})^{6-3}}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20P%283%3B6%2C%5Cdfrac%7B1%7D%7B2%7D%29%3DP%28X%3D3%29%3D%7B%5Cbinom%20%7B6%7D%7B3%7D%7D%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7B3%7D%281-%5Cdfrac%7B1%7D%7B2%7D%29%5E%7B6-3%7D%7D)
![{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{3}(\dfrac{1}{2})^{3}}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20P%283%3B6%2C%5Cdfrac%7B1%7D%7B2%7D%29%3DP%28X%3D3%29%3D%7B%5Cbinom%20%7B6%7D%7B3%7D%7D%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7B3%7D%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7B3%7D%7D)
![{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)={\binom {6}{3}}(\dfrac{1}{2})^{6}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20P%283%3B6%2C%5Cdfrac%7B1%7D%7B2%7D%29%3DP%28X%3D3%29%3D%7B%5Cbinom%20%7B6%7D%7B3%7D%7D%28%5Cdfrac%7B1%7D%7B2%7D%29%5E%7B6%7D)
![\binom {6}{3}=20](https://tex.z-dn.net/?f=%5Cbinom%20%7B6%7D%7B3%7D%3D20)
Hence,
![{\displaystyle P(3;6,\dfrac{1}{2})=P(X=3)=20\times (\dfrac{1}{2})^6=\dfrac{5}{16}](https://tex.z-dn.net/?f=%7B%5Cdisplaystyle%20P%283%3B6%2C%5Cdfrac%7B1%7D%7B2%7D%29%3DP%28X%3D3%29%3D20%5Ctimes%20%28%5Cdfrac%7B1%7D%7B2%7D%29%5E6%3D%5Cdfrac%7B5%7D%7B16%7D)
In percentage the probability will be:
![\dfrac{5}{16}\times 100=31.25\%=31.2\%](https://tex.z-dn.net/?f=%5Cdfrac%7B5%7D%7B16%7D%5Ctimes%20100%3D31.25%5C%25%3D31.2%5C%25)
Answer:
![Probability = 0.2975](https://tex.z-dn.net/?f=Probability%20%3D%200.2975)
Step-by-step explanation:
Giving:
<u>Swimming</u>
![P(Win[Swim])= 65\%](https://tex.z-dn.net/?f=P%28Win%5BSwim%5D%29%3D%2065%5C%25)
<u>Running</u>
![P(Win[Run])= 85\%](https://tex.z-dn.net/?f=P%28Win%5BRun%5D%29%3D%2085%5C%25)
<u>Required</u>
Determine the probability of winning at running and losing at swimming
First, we calculate the probability of losing at swimming using
![P(Win) + P(Lose) = 1](https://tex.z-dn.net/?f=P%28Win%29%20%2B%20P%28Lose%29%20%3D%201)
Substitute 65% for P(Win)
![65\% + P(Lose[Swim]) = 1](https://tex.z-dn.net/?f=65%5C%25%20%2B%20P%28Lose%5BSwim%5D%29%20%3D%201)
Collect Like Terms
![P(Lose[Swim]) = 1 - 65\%](https://tex.z-dn.net/?f=P%28Lose%5BSwim%5D%29%20%3D%201%20-%2065%5C%25)
![P(Lose[Swim]) = 35\%](https://tex.z-dn.net/?f=P%28Lose%5BSwim%5D%29%20%3D%2035%5C%25)
The required probability is then calculated using:
![Probability = P(Win[Run]) * P(Lose[Swim])](https://tex.z-dn.net/?f=Probability%20%3D%20P%28Win%5BRun%5D%29%20%2A%20P%28Lose%5BSwim%5D%29)
![Probability = 85\% * 35\%](https://tex.z-dn.net/?f=Probability%20%3D%2085%5C%25%20%2A%2035%5C%25)
Convert to decimal
![Probability = 0.85 * 0.35](https://tex.z-dn.net/?f=Probability%20%3D%200.85%20%2A%200.35)
![Probability = 0.2975](https://tex.z-dn.net/?f=Probability%20%3D%200.2975)